The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
From the question,
We are to factorize the expression (h+2k)²+4k²-h² completely
The expression can be factorized as shown below
(h+2k)²+4k²-h² becomes
(h+2k)² + 2²k²-h²
(h+2k)² + (2k)²-h²
Using difference of two squares
The expression (2k)²-h² = (2k+h)(2k-h)
Then,
(h+2k)² + (2k)²-h² becomes
(h+2k)² + (2k +h)(2k-h)
This can be written as
(h+2k)² + (h +2k)(2k-h)
Now,
Factorizing, we get
(h +2k)[(h+2k) + (2k-h)]
Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
Learn more here:brainly.com/question/12486387
Hello!
To find our answer, we first convert 1/2 into fourths. We multiply it by 2/2, giving us 2/4.
2/4+1/4=3/4
Therefore, our answer is
.
I hope this helps!
Answer:
Step-by-step explanation:
<u>Given</u>
- m∠ABC = x°
- m∠BCD = 25°
- m∠CDE = 55°
- m∠DEF = 3x°
Add two more parallel lines passing through points C and D.
Consider alternate interior angles formed by the four parallel lines.
<u>The angles between the two middle lines are equal to:</u>
- m∠BCD - m∠ABC = m∠CDE - m∠DEF
<u>Substitute values and solve for x:</u>
- 25 - x = 55 - 3x
- 3x - x = 55 - 25
- 2x = 30
- x = 15
m∠ABC = 15°
15% of 33 =
= 15% * 33
= 0.15 * 33
= 4.950 students in that class are left-handed