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grandymaker [24]
3 years ago
6

The volume of a cube is 124 cubic inches. What is the side length of the cube?

Mathematics
2 answers:
ivolga24 [154]3 years ago
8 0

Answer:

4.987 in

Step-by-step explanation:

Volume of a cube=  (where x= side)

x³

we know that

124=x³

∛124=x

x=4.986630952 which rounds to

4.987

Fantom [35]3 years ago
6 0

Answer: a≈4.99in

Step-by-step explanation:

Using the formula

V=a³

Solving for a

a=V <em><To Power></em> ⅓ =   124⅓ ≈ 4.98663in

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Can someone help me find the area
lisabon 2012 [21]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 116.12

Explanation:

13 x 7 = 91

13 - 5 = 8

8 / 2 = 4

3.14(4)^2 = 50.24

50.24 / 2 = 25.12

91 + 25.12 = 116.12

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

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3 years ago
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❊ Simplify :
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<h3>Need to Do :- </h3>
  • To simplify the given expression .

\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 }

\rule{200}4

\sf\longrightarrow \small  \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small  \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) }  \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5)  } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3}   \\\\\\\sf\longrightarrow   \small  \dfrac{1}{x-2} +\dfrac{2}{x-3}  \\\\\\\sf\longrightarrow   \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) }  \\\\\\\sf\longrightarrow   \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) }     \\\\\\\sf\longrightarrow   \underset{\blue{\sf Required \ Answer  }}{\underbrace{\boxed{\pink{\frak{  \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}

\rule{200}4

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