A car initially traveling at 24 m/s slams on the brakes and moves forward 196 m before coming to a complete halt. What was the m agnitude of the car's deceleration? A = 1.47 m/s 2
1 answer:
Answer:
Explanation:
We can use the following SUVAT equation to solve the problem:
where
v = 0 is the final velocity of the car
u = 24 m/s is the initial velocity
a is the acceleration
d = 196 m is the displacement of the car before coming to a stop
Solving the equation for a, we find the acceleration:
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speed = 86km/hr
= 86000/3600
= 23.889m/s
time = 4.6s
acceleration = 23.889/4.6
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