Your answer will be False because wavelengths are usually are use as sound waves.
Answer:
The work done by the bird is 0.762 J
Explanation:
Given;
force applied by the bird, f = 10 N
distance the bird moved the worm, d = 3 inches = 0.0762 m
The work done by the bird is given by;
W = F x d
where;
W is the work done by the bird
d is the distance the bird moved the load
Substitute the given values and estimate the work done by the bird;
W = 10 x 0.0762
W = 0.762 J
Therefore, the work done by the bird is 0.762 J
Answer:
No.
Explanation:
We shall solve this problem by calculating the resolving power of eye for given wavelength
Resolving Power of eye = \frac{1.22\lambda }{D}
Where λ is wave length of light and D is diameter of eye.
λ is 600 nm and D is 3.5 mm . Put these values in the given formula
Resolving Power = \frac{1.22\times 600\times 10^{-9} }{3.5\times 10^{-3}}\\
=209.14 \times 10^{-6}radian
From the formula
Φ = \frac{L}{D}[/tex]
Where Ф is resolving power . If L be distance between two points that can be resolved at distance D. D is 6 km or 6000 m .
209.14 \times 10^{-6}=\frac{L}{6000}\\
L= 1.254 m
So minimum distance that can be resolved is 1.254 m.
It shows all except the types of precipitation and created for newspapers
In order to calculate the weight, we may simply use:
W = mg
W = 30 * 9.81
W = 294.3 N
The sum of the reaction force and the upward component of child pulling will be equal to total downward force. The force acting downwards is the weight. Therefore:
R + 12sin(45) = 294.3
R = 285.82 N
The acceleration can be found using the resultant force and the mass of the sled. The resultant force is:
F(r) = pulling force + pushing force - friction
F(r) = 12cos(45) + 8 - 5
F(r) = 11.48 N
a = F/m
a = 11.48 / 30
a = 0.38 m/s²
