Ask question

Ask question

All categories

3 years ago

12

Is a vector necessarily changed if it is rotated through an angle ?Explain

1 answer:

gavmur [86]3 years ago

6 0

Yes, since it depends on the normal and resultant

You might be interested in

Why does a green leaf look green in our eyes

mamaluj [8]

They look green because of the “special pair” of chlorophyll molecules.

3 0

3 years ago

Read 2 more answers

What statement applies to the horizontal rows or periods in the periodic table? A. The properties are all the same. B. The eleme

Sliva [168]

The right answer for the question that is being asked and shown above is that: "C. <span>. The properties change going across each row. " the </span>statement that applies to the horizontal rows or periods in the periodic table is that t<span>he properties change going across each row. </span>

7 0

3 years ago

If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds

stepan [7]

Answer:

a) $s_{max} = 96\,ft$ , b) $v(4.449\,s) = -78.368\,\frac{ft}{s}$

Explanation:

a) The maximum height is obtained with the help of the First and Second Derivative Tests:

First Derivative

$v(t) = 64 - 32\cdot t$

$64 - 32\cdot t = 0$

$t = 2\,s$

Second Derivative

$a(t) = -32$ (absolute maximum)

The maximum height reached by the ball is:

$s (2\,s) = 32 + 64\cdot (2\,s) - 16\cdot (2\,s)^{2}$

$s_{max} = 96\,ft$

b) The time required by the ball to hit the ground is:

$32+64\cdot t - 16\cdot t^{2} = 0$

$-16\cdot (t^{2}-4\cdot t - 2) = 0$

$t^{2}-4\cdot t - 2 = 0$

$(t -4.449)\cdot (t+0.449)\approx 0$

Just one root offers a solution that is physically reasonable:

$t = 4.449\,s$

The velocity of the ball when it hits the ground is:

$v(4.449\,s) = 64 - 32\cdot (4.449\,s)$

$v(4.449\,s) = -78.368\,\frac{ft}{s}$

6 0

3 years ago

Read 2 more answers

One indicator NOT related to domestic violence is

Aleksandr-060686 [28]

Answer:

good nutrition

Explanation:

I think that one's pretty self explanatory

4 0

2 years ago

Work functions of tungsten and sodium are 4.4 eV and 2.3 eV respectively. If threshold

KonstantinChe [14]

Answer:

(d) 2840 A

Explanation:

Threshold frequency can be be calculated using expresion below

(λ)= hc/ Φ

(λ) sodium/ (λ)tungsten = Φtungsten/ Φsodium

But (λ) sodium is given as 5460 A,

Φsodium = 2.3 eV

Φtungsten= 4.4 eV

If we substitute the values we can find

(λ)tungsten.

(λ)tungsten= [(λ) sodium × Φsodium]/ Φtungsten

=( 5460× 2.3)/4.4

= 2854A

Hence, threshold wavelength of tungsten is 2854A

5 0

3 years ago