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Arada [10]
3 years ago
12

Is a vector necessarily changed if it is rotated through an angle ?​Explain

Physics
1 answer:
gavmur [86]3 years ago
6 0
Yes, since it depends on the normal and resultant
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Why does a green leaf look green in our eyes
mamaluj [8]
They look green because of the “special pair” of chlorophyll molecules.
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3 years ago
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What statement applies to the horizontal rows or periods in the periodic table? A. The properties are all the same. B. The eleme
Sliva [168]
The right answer for the question that is being asked and shown above is that: "C. <span>. The properties change going across each row. " the </span>statement that applies to the horizontal rows or periods in the periodic table is that t<span>he properties change going across each row. </span>
7 0
3 years ago
If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds
stepan [7]

Answer:

a) s_{max} = 96\,ft, b) v(4.449\,s) = -78.368\,\frac{ft}{s}

Explanation:

a) The maximum height is obtained with the help of the First and Second Derivative Tests:

First Derivative

v(t) = 64 - 32\cdot t

64 - 32\cdot t = 0

t = 2\,s

Second Derivative

a(t) = -32 (absolute maximum)

The maximum height reached by the ball is:

s (2\,s) = 32 + 64\cdot (2\,s) - 16\cdot (2\,s)^{2}

s_{max} = 96\,ft

b) The time required by the ball to hit the ground is:

32+64\cdot t - 16\cdot t^{2} = 0

-16\cdot (t^{2}-4\cdot t - 2) = 0

t^{2}-4\cdot t - 2 = 0

(t -4.449)\cdot (t+0.449)\approx 0

Just one root offers a solution that is physically reasonable:

t = 4.449\,s

The velocity of the ball when it hits the ground is:

v(4.449\,s) = 64 - 32\cdot (4.449\,s)

v(4.449\,s) = -78.368\,\frac{ft}{s}

6 0
3 years ago
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One indicator NOT related to domestic violence is
Aleksandr-060686 [28]

Answer:

good nutrition

Explanation:

I think that one's pretty self explanatory

4 0
2 years ago
Work functions of tungsten and sodium are 4.4 eV and 2.3 eV respectively. If threshold
KonstantinChe [14]

Answer:

(d) 2840 A

Explanation:

Threshold frequency can be be calculated using expresion below

(λ)= hc/ Φ

(λ) sodium/ (λ)tungsten = Φtungsten/ Φsodium

But (λ) sodium is given as 5460 A,

Φsodium = 2.3 eV

Φtungsten= 4.4 eV

If we substitute the values we can find

(λ)tungsten.

(λ)tungsten= [(λ) sodium × Φsodium]/ Φtungsten

=( 5460× 2.3)/4.4

= 2854A

Hence, threshold wavelength of tungsten is 2854A

5 0
3 years ago
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