The formation of Earth is supported by the statements like, it is a terrestrial planet. it was formed from gas and dust. it was formed in a debris disk from colliding planetesimals.
The given problem is based on the correct statements entitling the description of Earth. Earth is amongst 8 planets in our solar system, that happen to orbit around the sun.
The statements given to describe the Earth are as follows:
- Earth is not an Outer planet. It is an inner planet that lies closest to the sun after Mercury and Venus.
- Earth is a terrestrial planet because it is having a compact and rocky surface. Also, it is known to be an as largest terrestrial planet in the solar system with extensive regions of liquids and water.
- The abundant rocky surfaces have evolved from the cloud of dust and gas, during the post-Big Bang Era. So, it is somewhere true to say that Earth is formed from gas and dust.
- The earlier atmosphere of Earth was known for having proportional layers of Hydrogen and Helium. Hence is quite true to say that the Earth is having an atmosphere of Hydrogen and helium gases, but it is not as thick as the like sun.
- Majority of terrestrial planets are formed from the collision of planetesimals in a debris disk. With Earth being one of them, it is quite correct to consider the given statement.
Thus, we can conclude that the formation of Earth is supported by the statements like: it is a terrestrial planet, it was formed from gas and dust and it was formed in a debris disk from colliding planetesimals.
Learn more about the planet Earth here:
brainly.com/question/24878669
Answer:
The answer would be 0.04ohms.
Explanation:
Hopefully this helps
Answer: B, Companies passed on production and transportation costs to consumers
Explanation:
To solve the problem it is necessary to use Newton's second law and statistical equilibrium equations.
According to Newton's second law we have to
![F = mg](https://tex.z-dn.net/?f=F%20%3D%20mg)
where,
m= mass
g = gravitational acceleration
For the balance to break, there must be a mass M located at the right end.
We will define the mass m as the mass of the body, located in an equidistant center of the corners equal to 4m.
In this way, applying the static equilibrium equations, we have to sum up torques at point B,
![\sum \tau = 0](https://tex.z-dn.net/?f=%5Csum%20%5Ctau%20%3D%200)
Regarding the forces we have,
![3Mg-1mg=0](https://tex.z-dn.net/?f=3Mg-1mg%3D0)
Re-arrange to find M,
![M = \frac{m}{3}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7Bm%7D%7B3%7D)
![M = \frac{50}{3}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B50%7D%7B3%7D)
![M = 16.67Kg](https://tex.z-dn.net/?f=M%20%3D%2016.67Kg)
Therefore the maximum additional mass you could place on the right hand end of the plank and have the plank still be at rest is 16.67Kg
Answer:
6
Explanation:
Number of lines emanate from + 5 micro coulomb is 15 .
They terminates at negative charges that means at - 3 micro coulomb and - 2 micro Coulomb.
the electric field lines terminates at - 3 micro Coulomb and - 2 micro Coulomb is in the ratio of 3 : 2.
So the lines terminating at - 3 micro coulomb
= ![\frac{3}{5}\times 15 = 9](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D%5Ctimes%2015%20%3D%209)
So the lines terminating at - 2 micro coulomb
= ![\frac{2}{5}\times 15 = 6](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%5Ctimes%2015%20%3D%206)
So, the number of filed lines terminates at - 2 micro Coulomb are 6.