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seropon [69]
3 years ago
10

20%7B%20%7B%7D%5E%7B2%7D%20%7D%5E%7B%7D%20%7D%20%7D%20R" id="TexFormula1" title="I = \frac{E}{ \sqrt{R {}^{2} + W {}^{2} L { {}^{2} }^{} } } R" alt="I = \frac{E}{ \sqrt{R {}^{2} + W {}^{2} L { {}^{2} }^{} } } R" align="absmiddle" class="latex-formula">
Solve for R. Please help need answer ASAP. Pleased write explanation. Thank you...​
Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

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Vlada [557]

Answer:

(-6,4)

Step-by-step explanation:

You started at (-4,2)  The first number in the ordered pair moves the number left and right and the second number moved the point up and down.

We are first told to move the point 2 units to the left.  -4 is my left right number.  If I am at -4 and I go to unites to the left, I will be at -6.  My new point is now (-6,2).  Next we are told to go up 2.  The 2 number in my ordered pair tells me that I am 2 above the x axis.  Now I am going to go two more units up.  I am now at 4, so my new ordered pair after the translation is (-6,4)

8 0
2 years ago
Solve the following inequality for h then simplify <br> 8h-2&gt;3h+2
Nata [24]

Answer:

8h-3>3h +2

8h-3h>2+3

5h>5

h>1

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6 0
3 years ago
Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u
Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

z=\frac{x-\mu}{\sigma}

Plug in the values and solve for 'z'. This gives,

z=\frac{2.33-1.75}{0.22}=2.64

So, the z-score of the distribution is 2.64.

Now, we need the probability P(x\geq 2.33 )=P(z\geq  2.64).

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

P(z\geq  2.64)=1-0.9959=0.0041=0.41\%

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0
3 years ago
The U.S. and many other countries have recently tightened airport security. A sociologist is interested in estimating the propor
melisa1 [442]

Answer:

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

Step-by-step explanation:

Conduct a test to determine whether the true proportion of interest is higher than 0.7.

This means that the null hypothesis is: H_{0}: p = 0.7

And the alternate hypothesis is: H_{a}: p > 0.7

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7, \sigma = \sqrt{0.7*0.3}

The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.

This means that n = 500, X = \frac{375}{500} = 0.75

Value of the z-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.75 - 0.7}{\frac{\sqrt{0.7*0.3}}{\sqrt{350}}}

z = 2.44

P-value of the test:

Probability of z being larger than 2.44, that is, a proportion larger than 0.75.

This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S

Z = 2.44 has a pvalue of 0.9927

1 - 0.9927 = 0.0073

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

8 0
3 years ago
Jill Kingman pays a $419.00 premium annually. This represents 35% of the total premium. The rest of the premium is paid by her e
Leto [7]

Answer:

I think the answer is 1,466.50

8 0
3 years ago
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