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3 years ago

Pls help asapp plzzzz

Mathematics

1 answer:

ser-zykov [4K]3 years ago

4 0

The area would be 280 because if each side is 4 and there are 7 sides all you have to do is 4 times 7 which is 28 then do 28 times 10 since it’s the night and you get 280 as your area

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Pls help I really need help pls I need Profesional at math pls pls

Rzqust [24]

I think $6.75 for 15 juice boxes is better because, each juice box is 0.45.

While $5.50 for 11 juice boxes is 0.50.

And if we were to add 0.50 enough times to make 15 juice boxes it would equal 7.50

RIP OFFFFFFF

THE SECOND ONE IS A WAY BETTER OF A DEAL

4 0

3 years ago

F(x) = x2 – 2x - 8

maw [93]

Answer:

The y-intercept is the point (0,-8)

see the attached figure

Step-by-step explanation:

we have

$f(x)=x^{2}-2x-8$

we know that

The y-intercept is the value of the function f(x) when the value of x is equal to zero

For x=0

$f(x)=0^{2}-2(0)-8\\f(x)=-8$

therefore

The y-intercept is the point (0,-8)

see the attached figure to better understand the problem

5 0

3 years ago

Kassie is measuring two line segments. the first line segment is 35 centimetres long. the second line segment is 450 milimetres

Free_Kalibri [48]

1cm = 10mm
the 1st line segment is 35cm = 350mm
the 2nd line segment is 450mm = 45cm

6 0

3 years ago

Emma packed gift bags to give to the

Alex17521 [72]

Answer:

15 items Emma packed in the bag .

#Hope it helps!!

6 0

3 years ago

Read 2 more answers

The radius of the cone is 1.25 inches, and its height is 2.75 inches. If the diameter of the bubble gum ball is 0.5 inches, what

nasty-shy [4]

<h2>Explanation:</h2><h2></h2>

The volume of a cone can be found as:

$V=\frac{1}{3}\pi r^2 h \\ \\ \\ Where: \\ \\ V:Volume \\ \\ r:radius \ of \ base \\ \\ h:height$

Given the radius and height, we can find the volume of the cone:

$V=\frac{1}{3}\pi r^2 h \\ \\ V=\frac{1}{3}\pi (1.25)^2(2.75) \\ \\ V=\frac{1}{3}\pi(1.5625)(2.75) \\ \\ V\approx 4.5in^3$

The volume of a sphere is:

$V=\frac{4}{3}\pi r^3 \\ \\ \text{Each gum ball has a diameter of 0.5in, so the radius is:} \\ \\ r=\frac{0.5}{2}=0.25in$

So, for each gum ball the volume is:

$V=\frac{4}{3}\pi r^3 \\ \\ V=\frac{4}{3}\pi (0.25)^3 \\ \\ V=0.065in^3$

Therefore, the he closest approximation of the volume of the cone that can be filled with flavored ice is:

$4.5-0.065=4.43in^3$

Conclusion: The volume of the cone that can be filled with flavored ice is 4.43 cubic inches.

3 0

3 years ago