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Kaylis [27]
3 years ago
15

Can two events with nonzero probabilities be both independent and mutually​ exclusive? Choose the correct answer below. A. ​Yes,

two events with nonzero probabilities can be both independent and mutually exclusive when their probabilities add up to one. B. ​No, two events with nonzero probabilities cannot be independent and mutually exclusive because if two events are mutually​ exclusive, then when one of them​ occurs, the probability of the other must be zero. C. ​Yes, two events with nonzero probabilities can be both independent and mutually exclusive when their probabilities are equal. D. ​No, two events with nonzero probabilities cannot be independent and mutually exclusive because independence is the complement of being mutually exclusive.
Mathematics
1 answer:
Flura [38]3 years ago
3 0

Answer:

Step-by-step explanation:

B. ​No, two events with nonzero probabilities cannot be independent and mutually exclusive because if two events are mutually​ exclusive, then when one of them​ occurs, the probability of the other must be zero.

For two mutually exclusive events , with non- zero probabilities , when one occurs , the other can not happen . In this way they become dependent events . In this way , for two events to be both independent and mutually exclusive , at least one of the two events must have zero probability .

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1. A relation is plotted as a linear function on a coordinate plane starting at point C at (3, –2) and ending at point D at (–2,
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Hi I need this asap if you also explain the work on how you got answers plz and thank you<br>​
weeeeeb [17]

Answer:

<u>Q/ Draw a line ; Ans; </u>

\frac{9}{5}  —>1 \frac{4}{5}

*explain ; We put the 5 in the denominator and 5 multiply 1 + 4 so equal 9 so the choice 9/5 .

Ans; 7/3—> 2 1/3

*explain ; We put the 3 in the denominator and 3 multiply 2 + 1 so equal 7 so the choice 7/3 .

Ans; 12/10 —> 1 1/5

*explain; simple (12 and 10) ÷ 2 so equal 6/5

We put the 5 in the denominator and 5 multiply 1 + 1 so equal 6 so the choice 6/5 =12/10 .

\frac{12 \div 2}{10 \div 2}  =  \frac{6}{5}  = 1 \frac{1}{5}

<u>Q/ Compare the fractions;Ans;</u>

\frac{2}{3}  <  \frac{14}{6}

* explain; 2/3 = 0.66 and 14/6=2.33 so 2.33 greater from 0.66 so 14/6 greater from 2/3 .

\frac{3}{8}  <  \frac{8}{3}

* explain; 3/8 = 0.375 and 8/3=2.666 so 2.666 greater from 0.375 so 8/3 greater from 3/8 .

2  \frac{1}{6}  >  \frac{5}{9}

* explain; 2 1/6 —> We put the 6 in the denominator and 6 multiply 2 + 1 so equal 13 so equal 13/6

13/6 = 2.16 and 5/9=0.55 so 2.16 greater from 0.55 so 13/6 = 2 1/6 greater from 5/9 .

<u>Q/Add; Ans;</u>

\frac{7}{8}  +  \frac{5}{8}  =  \frac{7 + 5}{8}  =  \frac{12}{8}  =  \frac{3}{2}

\frac{1}{9}  +  \frac{2}{3}  \\  \\  \frac{1}{9}  +  \frac{6}{9}  =  \frac{ 1+6 }{9}  =  \frac{7}{9}

<u>Q/Subtract; Ans;</u>

\frac{6}{7}  -  \frac{4}{7}  =  \frac{6 - 4}{7}  =  \frac{2}{7}

\frac{7}{3}  -  \frac{2}{9}  \\  \\  \frac{21}{9}  -  \frac{2}{9}  =  \frac{21 - 2}{9}  =  \frac{19}{9}

<u>Q/ Multiply;Ans;</u>

\frac{1}{5}  \times  \frac{1}{2}  =  \frac{1}{10}

\frac{2}{3}  \times  \frac{3}{8}  =  \frac{6}{24}  =  \frac{1}{4}

<u>Q/Divide;Ans;</u>

\frac{3}{4}  \div  \frac{2}{5}  \\  \\  \frac{3}{4}  \times  \frac{5}{2}  =  \frac{15}{8}

\frac{8}{9}  \div  \frac{1}{3}  \\  \\  \frac{8}{9}  \times  \frac{3}{1} =   \frac{24}{9}  =  \frac{8}{3}

I hope I helped you^_^

5 0
3 years ago
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