Please help: What is 4 1/4 divided by 3/4 equal?

Romashka [77]

$\bf \cfrac{3.7\times 10^{-12}(42)}{(.000000025)(4.0\times 10^{-15})}\implies 
\cfrac{37\times 10^{-13}(42)}{(25\times 10^9)(4\times 10^{-15})}$

$\bf \cfrac{37(42)\times 10^{-13}}{25(4)\times 10^910^{-15}}\implies 
\cfrac{1554\times 10^{-13}}{100\times 10^{9-15}}\implies 
\cfrac{1554\times 10^{-13}}{1\times 10^2\times 10^{9-15}}
\\\\\\
\cfrac{1554\times 10^{-13}}{10^{2+9-15}}\implies \cfrac{1554\times 10^{-13}}{10^{-4}}\implies 1554\times 10^{-13}\times 10^4
\\\\\\
1554\times 10^{-13+4}\implies 1554\times 10^{-9}\implies \cfrac{1554}{10^9}\implies 0.000001554$

8 0

4 years ago

How are the following three expressions different from each other, if indeed they are? do not just state the value of each but e

Lisa [10]

Answer:

Below.

Step-by-step explanation:

Number is different to the other 2. Its value is +4 because negative 2 squared = + 4.

The other 2 have negative values and -2 = -(2) so they have the same value, -4.

8 0

3 years ago

10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.

erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

$p = \frac{4}{6} = 0.6667$

10 normal six sided dice are thrown.

This means that $n = 10$

Find the probability of obtaining at least 8 failures.

This is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951$

$P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867$

$P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174$

Then

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992$

0.2992 = 29.92% probability of obtaining at least 8 failures.

8 0

3 years ago

This is another question i need help with.

alina1380 [7]

Answer:

C, this diagram will show 2 1/3- 2/3 which is 7/3-2/3 which is 5/3 which is 1 2/3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The height of an object thrown upward with an initial velocity of 32 feet per second is given by the formula h = −16t2 + 32t, wh

andre [41]

Answer:

Therefore after 1 second of lunched the object reach a height of 16 feet.

Step-by-step explanation:

When a particle is thrown vertically upward direction on that time only gravitation force is worked on it. In that case the acceleration of the particle is - g.Since gravitation force works downward direction and the displacement of the particle is upward direction that's why acceleration is negative.

When particle comes down the the acceleration of the particle is g.

Since the displacement and acceleration work on the particle in same direction.

The value of g is 9.8 m/s².

Given that, the height of the particle can measure from the equation

$h=-16t^2+32t$ Where t is time in second

To find out the time when the object reach a height 16 feet. We have put the value of h in the given equation.

Putting h=16 in the given equation

16= -16 t²+32

⇒16t²-32t+16=0

⇒16(t²-2t+1)=0

⇒t²-2t+1=0² [ ∵16≠0]

⇒(t-1)²=0

⇒t-1=0

⇒t=1

Therefore after 1 second of lunched the object reach a height of 16 feet.

6 0

3 years ago