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Lelechka [254]
3 years ago
6

Please help: What is 4 1/4 divided by 3/4 equal?

Mathematics
1 answer:
Solnce55 [7]3 years ago
7 0
4/3 because I typed in on my calculator
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Choose 5 ordered pairs whose first component is the additive inverse of the second component. Plot these points and connect them
Lerok [7]
Let ordered pairs
 X Y
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<span>  What kind of figure do you get? 
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</span><span> y = -x
</span><span> In what quadrants does the figure lie?
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3 years ago
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253 = y − 326<br> what is y
Murrr4er [49]
To work out do the inverse
253+326
579

Then check it by doing 579-326
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Y=579
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3 years ago
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The machine bottled 8,000 bottles in 4 hours. if the rate of the machine were doubled, how long would it take the machine to bot
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It would take 20 hours since 8,000 times 5 is 40,000 so 4 times 5 is 20.



Logic.
4 0
4 years ago
What is the solution of the equation (x – 5)2 3(x – 5) 9 = 0? use u substitution and the quadratic formula to solve.
Ahat [919]

The value of x in the equation (x-5)^{2} +3(x-5)+9=0is x=(7+3\sqrt{3}i)/2,

(7-3\sqrt{3}i)/2.

Given equation (x-5)^{2} +3(x-5)+9=0 .

We have to find the solution of the equation.

Equation  is solved to find the value of variables. The number of values of the variable depends on the highest power of variables.

let (x-5)=u-------------------1

equation becomes u^{2} +3u+9=0

solution of a quadratic formula

x=-b±\sqrt{b^{2} -4ac}/2a

on comparing with general form a=1,b=3, c=9

u=-3±\sqrt{3^{2} -4*1*9} /2

=-3±\sqrt{9-36}/2

=-3±3\sqrt{-27}/2

=-3±3\sqrt{3} i/2

u_{1} =-3+3\sqrt{3}/2 , u_{2}=-3-3\sqrt{3}/2

put the values of u_{1} in equation 1

x-5=u_{1}

x-5=-3+3\sqrt{3} /2

x=-3+3\sqrt{3}i/2+5

x=7+3\sqrt{3} i/2

put the values of u_{2} in  equation2

x-5=u_{2}

x-5=-3-3\sqrt{3} /2

x=7-3\sqrt{3}/2

Hence the values of x are 7+3\sqrt{3}i/2, 7-3\sqrt{3}i/2.

Learn more about equation at brainly.com/question/2972832

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5 0
2 years ago
A rectangular gym has an area of 4x2 ft2. The school decides to add a new weight room. The total area of the gym and the weight
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C. 

The 520 is the new thing added to the equation, which makes it equal to the new weight room's size. 
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