1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marina CMI [18]
3 years ago
9

The two-way frequency table represents data from a survey asking mall visitors whether they like seafood, meat, or both. A 4-col

umn table with 3 rows. The first column has no label with entries seafood, not seafood, total. The second column is labeled meat with entries 16, 20, 36. The third column is labeled not meat with entries 31, 5, 36. The fourth column is labeled total with entries 47, 25, 72. Which is the joint relative frequency for mall visitors who like seafood and meat? StartFraction 5 Over 72 EndFraction StartFraction 16 Over 72 EndFraction StartFraction 20 Over 72 EndFraction StartFraction 31 Over 72 EndFraction
Mathematics
2 answers:
gladu [14]3 years ago
5 0

Answer:

Option B.

Step-by-step explanation:

The given table is

                          Meat              Not meat         Total

Seafood               16                      31                  47

Not seafood        20                      5                  25

Total                     36                    36                  72

From the given table it is clear that:

Seafood-Meat = 16

Not seafood-Meat = 20

Seafood-not meat = 31

Not seafood- not meat = 5

Total = 72

We need to find the joint relative frequency for mall visitors who like seafood and meat.

Joint relative frequency =\dfrac{\text{who like seafood and meat}}{\text{Total}}

Joint relative frequency =\dfrac{16}{72}

Therefore, the correct option is B.

Sedbober [7]3 years ago
5 0

Answer:

The Answer On Edge Is B.), Have Fun Dreamers!

Step-by-step explanation:

You might be interested in
Find all possible values of x in the similar triangles pqr stu
antoniya [11.8K]
If triangles PQR and STU are similar then PQ corresponds to ST and PR corresponds to SU. Therefore, PQ/ST=PR/SU
Considering that, PQ= 7-x, ST= 13-x, PR= x²+5 and SU= x² +20
therefore, (7-x)/(13-x)= (x²+5)/(x²+20) 
               cross multiplying,
         7x² +140-x³+20x =13x²+65-x³-5x
combining the like terms,
          6x² +15x -75=0
          solving for x,
    x = 5/2 or -5 
5 0
3 years ago
Which of the following is the reciprocal of 1 2/3
lana66690 [7]
The reciprocal is B. 3/5
6 0
3 years ago
Read 2 more answers
When writing number to word when do we put comma and dash
Alexandra [31]
Easy¡¡!!!!¡

It's starts with 1000
u put the comma after the 1 1,000

10000
10,000

100000
100,000

and so on......
4 0
3 years ago
How did the Germanic tribes govern thier kingdoms
Verdich [7]

The Germanic tribes were governed by unwritten costumes.

3 0
4 years ago
Express 0.000041 in scientific notation
nydimaria [60]
Starting at 4 count to the left, there's 5 zero
so answer

<span>0.000041 = 4.1 x 10^-5</span>
3 0
3 years ago
Read 2 more answers
Other questions:
  • Evaluate the function below at x=5. Then, enter your solution. f(x)=3(2)^x
    9·1 answer
  • AB has coordinates A(-15,5) and B(0-10). Find the coordinates of A' B'
    11·1 answer
  • Arie ran an equal number of miles each day for 12 days. He ran 60 miles in total.
    7·2 answers
  • Interpret this probability. choose the correct answer below.
    14·1 answer
  • What is the value of x in the equation below?
    7·2 answers
  • In which of the expressions below will x = 2.5? Select all that apply. A) 10x+209=5 B) 10x–12=38 C) 9x+18=45 D) 6x=15 E) 12x–4=2
    15·1 answer
  • Cindy can decorate 84 ornaments in 14 hour. How many ornaments, per hour, can Cindy decorate? A. 3 ornaments per hour O B. 16 or
    8·1 answer
  • Which of the following is a factor from problem #1?<br><br> 1) X^2 -3x -10
    7·1 answer
  • How do u delete questions lol
    9·2 answers
  • Please help me with this MATH question.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!