Question

What is an equation of the line that passes through the point (-6, -7) and is

Answer 1

Answer:

Step-by-step explanation:

Product of slope of perpendicular lines = -1

6x + 5y = 30

Write this equation in y = mx + b  form

        5y = -6x + 30

          y = $\frac{-6}{5}x+\frac{30}{5}$

          $y=\frac{-6}{5}x + 6$

Slope of this line m₁ = -6/5

m₁ * m₂ = -1

      m₂ = -1÷m₁ = -1 * $\frac{5}{-6}$  

$m_{2}=\frac{5}{6}$     & (-6 , -7)

Equation of the required line: y - y₁ = m (x - x₁)

$y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2$