Well I would think all of them in some way. For the first one, students need to collect data (whether it’s mathematical, scientific, etc.) to answer a question. For the second one, they may need to know how much money is in there bank account or they may need to calculate a sale to order the item. For the third one, they may need statistical data to support a position. For the last one, a student could use technological data to be able to solve their problem sorting documents.
When someone may be giving away something for free.
Answer:
Check the explanation
Explanation:
1.
System = 256Byte = 8 bit
Cache = 64B , block size = 16 byte.
A) Direct Mapped Cache:
Block offset = log (Block size) = log 16 = 4bit
Total # of block inside cache = 4.
Therefore index offset = log 4 = 2bit.
Remaining is tag bits.
Therefore tag bits = 8-(4+2) = 8-6 = 2 bits
Tag Index offset Block offset
(2 bits) (2 bits) (4 bits)
Fully associative cache :
In fully associative cache, any of main memory block can be placed anywhere in cache. Therefore index offset =0 bits.
Therefore tag bits = 8-block offset bit= 8-4 =4bits
Tag Block offset
(4 bits) (4 bits)
Answer:
Try checking around on the router!
Explanation:
Assuming they haven't changed it, most routers have their default password displayed somewhere on it. I hope this helps!! ^^
Answer:
d. Information governance board
Explanation:
In 2004 <em>Intel </em>was in need of a governance process as part of the company’s policy of <em>Intel’s Information Management (IMM)</em>. Such policies and governance were important in the corporation’s process in order to mirror the local laws as well as to reproduce Intel’s dynamic nature of its activities as a corporation. The <em>Information Governance Boards </em>were intended for every main data area of the company: <em>location, item, finance, customer, supplier, and worker</em>. Such Governance Boards would engage business people in the company to embrace the stipulated policies also with the purpose of proptecting information.
