Answer:
SSS is the congruence theorem that can be used to prove Δ LON is congruent to Δ LMN ⇒ 1st answer
Step-by-step explanation:
Let us revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
- HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ
In triangles LON and LMN
∵ LO ≅ LM ⇒ given
∵ NO ≅ NM ⇒ given
∵ LN is a common side in the two triangles
- That means the 3 sides of Δ LON are congruent to the 3 sides
of Δ LMN
∴ Δ LON ≅ LMN ⇒ by using SSS theorem of congruence
SSS is the congruence theorem that can be used to prove Δ LON is congruent to Δ LMN
The value of the question mark I 8.
Step by step solution:
Values:
Brown frosted donut: 3
Orange frosted donut: 1/3
White frosted donut: 1
Hope this helps!! :)
Answer -4/27
-1/9 x 4/3 will give you -4/27
Answer For two events A and B,P(A)−0.36,P(B)−0.37, and P(A∩B)−0.11 a. Find P(A∣B). b. Find P(B∣A). c. Determine whether or not A and Bare independent. I think
Step-by-step explanation:
We have to functions, namely:
So the problem is asking for the smallest positive integer for
so that
is greater than the value of
, that is:
Let's solve this problem by using the trial and error method:
So starting
from 1 and increasing it in steps of one we find that:
when
That is,
the smallest positive integer for
so that the function
is greater than
is 4.
