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poizon [28]
4 years ago
11

Suppose I flip two identical coins. What is the probability that I get one head and one tail?

Mathematics
2 answers:
Alexeev081 [22]4 years ago
7 0
50/50 chance to be wrong or right
Yuliya22 [10]4 years ago
3 0

Answer:0.5


Step-by-step explanation:

possibilities for two coins are {(h,t),(t,h),(h,h),(t,t)}

=2/4=0.5

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What is a correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9?
Masteriza [31]

Answer:

<em>-12 + 20x ≥ -6x + 9</em>

<em>Fourth choice</em>

Step-by-step explanation:

<u>Inequalities</u>

We are given the inequality:

-4(3 - 5x) ≥ -6x + 9

Solving the inequality implies having x isolated on one of the sides.

We must start by removing the parentheses. It will be done by multiplying -4 by (3 - 5x). Since this operation doesn't imply multiplying all the inequality by a negative number, the sign won't be flipped:

-4*3 - (-4)5x ≥ -6x + 9

Multiplying:

-12 + 20x ≥ -6x + 9

Fourth choice

8 0
3 years ago
30/x = 54/81 what value does x have to be to make it true
Dafna11 [192]

Answer:

x=45

Step-by-step explanation:

30/x = 54/81

30 = 54/81(x)

x = 30 ÷ 54/81

x=45

5 0
3 years ago
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Vera_Pavlovna [14]

Answer:

A. t = -2h + 32

7 0
3 years ago
Look at picture. What is the solution WORTH 10 points. Show work.
lakkis [162]

\left\{\begin{array}{ccc}2x-y=6\\2x-2y=4&|\text{add 2y to both sides}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\2x=4+2y&|\text{divide both sides by 2}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\x=2+y\end{array}\right\\\\\text{Substitute x=2+y to the first equation}\\\\2(2+y)-y=6\ \ \ \ |\text{use distributive property}\\(2)(2)+(2)(y)-y=6\\4+2y-y=6\\4+y=6\ \ \ \ \ |\text{subtract 4 from both sides}\\\boxed{y=2}\\\\\text{Put the value of y to the second equation}\\\\x=2+2\\\boxed{x=4}

Answer:\ D.\ (4,\ 2)

8 0
4 years ago
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56 in²
garri49 [273]

The area of the remaining board is [(L × B) - (l × b)].

According to the statement

We have to find that the area of the remaining board.

So, For this purpose, we know that the

Area of rectangle is the region occupied by a rectangle within its four sides or boundaries. The area of a rectangle depends on its sides.

From the given information:

Suppose the bigger rectangle is labelled as ABCD and the smaller rectangle is labelled as PQRS.

And

Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.

The area of any rectangle is:

Area = Length × Breadth

The area of the bigger rectangle is:

Area of ABCD = L × B

The area of the smaller rectangle is:

Area of PQRS = l × b

Then the area of the remaining board will be:

Area of remaining board = Area of ABCD - Area of PQRS

Area of remaining board= (L × B) - (l × b)

Thus, The area of the remaining board is [(L × B) - (l × b)].

Learn more about Area here

brainly.com/question/8409681

Disclaimer: This question was incomplete. Please find the full content below.

Question:

A rectangle is removed from the middle of a larger rectangular shaped board. What is the area of the remaining board?

#SPJ9

6 0
1 year ago
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