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SCORPION-xisa [38]
4 years ago
13

If the domain is {0, 2, -6}, what is the range of y = -2x + 3?

Mathematics
1 answer:
ZanzabumX [31]4 years ago
5 0

Answer:

{-1, 3, 15}

Step-by-step explanation:

Domain is the set of all inputs

Range is the set of all outputs

x = 0, y = -2(0)+3 = 3

x = 2, y = -2(2)+3 = -1

x = -6, y = -2(-6)+3 = 15

Range: {-1,3,15}

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(4 points) A bit string is a sequence of 0s and 1s.How many bit strings of length 12 either start with 0000 or end with 1111
marta [7]

Answer:

The answer is "496"

Step-by-step explanation:

It begins at 0000 or finishes at 1111:

= 2^8 + 2^8 - 2^4\\\\= 256 +256 -16\\\\= 512 - 16 \\\\= 496                  

8 0
3 years ago
Write an exponential function whose graph contains the points (1, 6) and (0, 2).
12345 [234]

Answer:

y = 2 (3)^{x}

Step-by-step explanation:

The exponential function is of the form

y = a (b)^{x}

To find a and b substitute the given points into the equation

Using (0, 2), then

2 = a (b)^{0} ⇒ a = 2

Using (1, 6), then

6 = 2 (b)^{1} ⇒ b = 3

Equation is y = 2 (3)^{x}

6 0
3 years ago
Add or subtract. Write the answer in standard form. 7−(3+4i)+6i
Alisiya [41]

Answer:

4 + 2i

Step-by-step explanation:

First distribute;

7 - 3 - 4i + 6i

= 4 + 2i

3 0
3 years ago
A barrel shaped like a cylinder is laid on its side and rolled up a ramp that is 92m long. The barrel has a circular base that t
Schach [20]
92/46ths of a meter or 2 meters
8 0
4 years ago
Einsteinium-
Natalija [7]

Answer:

                 S(t)=450(2/3)^t

Explanation:

The question is "Einstenium-253 is an element that loses about 2/3 of its mass every month. A sample of einstenium-253 has 450 grams. Write a function that gives the sample's mass in grams, S(t) from today".

Since <em>einstenium-253 loses about 2/3 of its mass every month</em>, you can model the amount of sample by an exponential decay function, which is a geometric progression with a growing factor less than 1.

The general form of an exponential decay function is:

y=A_0r^t

Where:

  • A₀ is the initial value
  • r is the growing or decaying factor
  • t is the time
  • y is the value of the function at time t.

In this case, you have:

  • A₀ = 450
  • r = 2/3
  • t = t
  • y = S(t)

Now you can replace the values in the model and will obtain:

                  S(t)=450(2/3)^t

4 0
3 years ago
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