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marissa [1.9K]
3 years ago
7

WHOEVER ANSWERS FIRST GETS BRAINLIEST AND 100 POINTS 0.1*√20000 -0.05*√28800

Mathematics
1 answer:
____ [38]3 years ago
8 0

Answer:

0.1*√20000 = 14.1421356237

-0.05*√28800 = -8.48528137424

Step-by-step explanation:

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Which of the following does not represent an integer.
sveticcg [70]

Answer: C

Step-by-step explanation:

4 0
3 years ago
an Italian restaurant buys 15 pounds of onions every 2 weeks. how many bags of onions will the restaurant buy in 7 weeks?
Arturiano [62]

Answer:

45

Step-by-step explanation:

This is a trick question. Since they only get three purchases in by 7 weeks, the answer will be 15 times 3 or 45.

(If I'm wrong and it's not a trick question, then it's 15 times 3.5 or 52.5)

Hope this helps!

5 0
3 years ago
8h + (-7.9d) - 14 + 5d - 3.4h
Fynjy0 [20]

☁️ Answer ☁️

So I got:

-2.9d + 4.6h - 14

Hope it helps.

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7 0
3 years ago
The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with
kvasek [131]

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

<h3>What is the average of five consecutive integers ending with b?</h3>

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

brainly.com/question/24369824

#SPJ1

7 0
1 year ago
Please help!
Aleks [24]

Answer:

Probability of picking an even and then even number = \frac{1}{6}

Step-by-step explanation:

Probability of picking a card with even number,

P(even 1) = \frac{\text{favorable outcomes}}{\text{Total outcomes}} = \frac{\text{even cards}}{\text{Total number of cards}}

               = \frac{2}{4}

               = \frac{1}{2}

Followed by picking a card which is even without putting the first card back.

So an even card is to be picked out of remaining 3 cards.

P(even 2) = \frac{\text{favorable outcomes}}{\text{Total outcomes}}

                = \frac{1}{3}

Now probability of both events = P(even 1) × P(even 2)

= \frac{1}{2}\times \frac{1}{3}

= \frac{1}{6}

Therefore, probability of both the events will be \frac{1}{6}.

5 0
3 years ago
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