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dangina [55]
2 years ago
14

How many moles of potassium are in 3.78 x 10^21 atoms of K?

Chemistry
1 answer:
lbvjy [14]2 years ago
3 0

Answer: 6.3 x 10^-3 moles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of potassium = 6.02 x 10^23 atoms

Z moles = 3.78 x 10^21 atoms

To get the value of Z, we cross multiply:

(3.78 x 10^21 atoms x 1mole) = (6.02 x 10^23 atoms x Z moles)

3.78 x 10^21 = (6.02 x 10^23 x Z)

Z = (3.78 x 10^21) ➗ (6.02 x 10^23)

Z = 0.63 x 10^-2)

Place the result in standard form

Hence, Z = 6.3 x 10^-3 moles

Thus, there are 6.3 x 10^-3 moles of potassium in 3.78 x 10^21 atoms of K.

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Answer:

Final concentration of NaOH = 0.75 M

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For NaOH :-

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The expression for the molarity, according to its definition is shown below as:

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Given, Volume = 3.00 L

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Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M

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Hello there!

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