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3 years ago

How many neutrons would an atom of fluorine have?

Chemistry

2 answers:

disa [49]3 years ago

8 0

Answer:

the ansewer would be nine

Explanation:

lord [1]3 years ago

6 0

Answer:

Explanation:

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How manymoles of each ion are present in 175 mL of 0.147 M Fe2(SO4)3?

lilavasa [31]

Answer: 0.0257 moles of $Fe^{3+}$ and 0.0257 moles of $SO_4^{2-}$

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{moles}{\text {Volume in L}}$

moles of $Fe_2(SO_4)_3=Molarity\times {\text {Volume in L}}=0.147\times 0.175L=0.0257moles$

The balanced reaction for dissociation will be:

$Fe_2(SO_4)_3\rightarrow Fe^{3+}+SO_4^{2-}$

According to stoichiometry:

1 mole of $Fe_2(SO_4)_3$ gives 1 mole of $Fe^{3+}$ and 1 mole of $SO_4^{2-}$

Thus there will be 0.0257 moles of $Fe^{3+}$ and 0.0257 moles of $SO_4^{2-}$

8 0

3 years ago

How many moles of N2 in 57.1 g of N2?

SpyIntel [72]

We are given –

Mass of $\bf N_2$ is 57.1 g and we are asked to find number of moles present in 57.1 g of $\bf N_2$

$\qquad$ $\pink{\bf\longrightarrow { Molar \:mass \:of \: N_2:-} }$

$\qquad$ $\bf \twoheadrightarrow 14\times 2$

$\qquad$ $\bf \twoheadrightarrow 28$

$\qquad$ ____________________

Now,Let's calculate the number of moles present in 57.1 g of $\bf N_2$

$\qquad$ $\purple{\bf\longrightarrow { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}$

$\qquad$ $\bf \twoheadrightarrow \dfrac{57.1}{28}$

$\qquad$ $\bf \twoheadrightarrow 2.04\: moles$

__________________________________

7 0

2 years ago

On a hot day, you sit on the edge of a pool and dip your feet into the water, causing changes to occur that are related to the p

Pani-rosa [81]

The answer is b and d

4 0

3 years ago

[Ca2+] within the endoplasmic reticulum (ER) is 10-3M. Cytosolic [Ca2+] is 10-7M. Lysosomes in mammalian cells have an internal

Pani-rosa [81]

Answer:

B. Ca2+ import into the ER because it has the steeper concentration gradient

Explanation:

ΔGt = RT㏑(C₂/C₁)

where ΔGt is the free energy change for transport; R = 8.315 J/mol; T = 298 K; C₂/C₁ is ratio of concentrations inside and outside each organelle.

For Ca²⁺ import

ΔGt = 8.315 J/mol * 298 K * ㏑(10⁻³/10⁻⁷)

ΔGt= 3.42 kJ/mol

For H⁺ import

ΔGt = 8.315 J/mol * 298 K * ㏑ (10⁻⁴/10⁻⁷)

ΔGt = 2.73 kJ/mol

From the above values, ΔGt is greater for Ca²⁺ import because it has a steeper concentration gradient

8 0

3 years ago

you are given a solution of lead nitrate. use any of the solution used in this experiment to form a white precipitate of lead ch

Vesnalui [34]

We have as a reagent a salt, lead nitrate (Pb(NO3)2), and an unknown solution that gives us as a product lead chloride (PbCl2). That is, the solution must contain chlorine.

If a chlorine solution is used we will have the following reaction:

$Pb(NO_{3)2}+2Cl^-\rightarrow PbCl_2+2NO^-_3$

So, with a chlorine solution, we will have a white precipitate of lead chloride.

7 0

1 year ago