Question

A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample starts off at 97.8 °C and the temperature of the water starts off at 17.0 °C. When the temperature of the water stops changing it's 19.3 °C. The pressure remains constant at 1 atm. insulated container water sample Calculate the specific heat capacity of quartz according to this experiment. Be sure your answer is rounded to 2 significant digits. a calorimeter g °C.

Answer 1

Answer:

The specific heat capacity of quartz is 0.71 J/g°C.

Explanation:

Heat lost by quartz will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of quartz= $m_1=51.9 g$

Specific heat capacity of quartz= $c_1=?$

Initial temperature of the quartz= $T_1=97.8^oC$

Final temperature = $T_2=T = 19.3^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water=$m_2=300.0 g$

Specific heat capacity of water= $c_2=4.18 J/g^oC$

Initial temperature of the water = $T_3=17.0 ^oC$

Final temperature of water = $T_2=T=19.3^oC$

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(51.9 gc_1\times (19.3^oC-97.8^oC))=300.0 g\times 4.18 J/g^oC\times (19.3^oC-170^oC)$

we get:

$c_1 =0.7079 J/g^oC\approx 0.71 J/g^oC$

The specific heat capacity of quartz is 0.71 J/g°C.