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marta [7]
3 years ago
12

A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample star

ts off at 97.8 °C and the temperature of the water starts off at 17.0 °C. When the temperature of the water stops changing it's 19.3 °C. The pressure remains constant at 1 atm. insulated container water sample Calculate the specific heat capacity of quartz according to this experiment. Be sure your answer is rounded to 2 significant digits. a calorimeter g °C.
Chemistry
1 answer:
Trava [24]3 years ago
5 0

Answer:

The specific heat capacity of quartz is 0.71 J/g°C.

Explanation:

Heat lost by quartz will be equal to heat gained by the water

-Q_1=Q_2

Mass of quartz= m_1=51.9 g

Specific heat capacity of quartz= c_1=?

Initial temperature of the quartz= T_1=97.8^oC

Final temperature = T_2=T  = 19.3^oC

Q_1=m_1c_1\times (T-T_1)

Mass of water=m_2=300.0 g

Specific heat capacity of water= c_2=4.18 J/g^oC

Initial temperature of the water = T_3=17.0 ^oC

Final temperature of water = T_2=T=19.3^oC

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(51.9 gc_1\times (19.3^oC-97.8^oC))=300.0 g\times 4.18 J/g^oC\times (19.3^oC-170^oC)

we get:

c_1 =0.7079 J/g^oC\approx 0.71 J/g^oC

The specific heat capacity of quartz is 0.71 J/g°C.

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