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3 years ago

Using the box-and-whisker plot shown, find the quartile values Q1 and Q3

Mathematics

1 answer:

astra-53 [7]3 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

The lower quartile $Q_{1}$ is positioned at the left side of the box, that is

$Q_{1}$ = - 4

The upper quartile $Q_{3}$ is positioned at the right side of the box

$Q_{3}$ = 6

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Help please thank you giving 15 pts

slega [8]

Answer:

x=22

Step-by-step explanation:

2x-40+8x=180

10x=220

x=22

8 0

3 years ago

Read 2 more answers

1. How do you determine the constant that you should add to an expression in the form x^2+bx so that it becomes a perfect square

Arada [10]

now heres a step by step explanation Step-by-step explanation: your welcome

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3 years ago

The 2008 Workplace Productivity Survey, commissioned by LexisNexis and prepared by World One Research, included the question, "H

LenaWriter [7]

Answer:

A 95% confidence interval estimate of the mean number of hours a legal professional works on a typical workday is [7.44 hours, 10.56 hours].

Step-by-step explanation:

We are given that x is normally distributed with a known standard deviation of 12.6.

A sample of 250 legal professionals was surveyed, and the sample's mean response was 9 hours.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average mean response = 9 hours

$\sigma$ = population standard deviation = 12.6

n = sample of legal professionals = 250

$\mu$ = mean number of hours a legal professional works

Here for constructing a 95% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $9-1.96 \times {\frac{12.6}{\sqrt{250} } }$ , $9+1.96 \times {\frac{12.6}{\sqrt{250} } }$ ]

= [7.44 hours, 10.56 hours]

Therefore, a 95% confidence interval estimate of the mean number of hours a legal professional works on a typical workday is [7.44 hours, 10.56 hours].

5 0

2 years ago

2х + Зу = -6 4х + бу = -12

Studentka2010 [4]

What is the question?

3 0

2 years ago

Math Solve the equation:-

Katena32 [7]

Answer:

y = -27

Step-by-step explanation:

Multiply the entire equation by 6

$\sf 6*\dfrac{y+1}{3}-6*\dfrac{3y-1}{6}=6*5\\\\\\$

2*(y + 1) - (3y - 1 ) = 30

Multiply (y +1) by 2 and (3y - 1) by (-1)

2y + 2 - 3y + 1 = 30

Isolate y term by taking the constant term to RHS

2y - 3y = 30 - 2 - 1

Combine like terms

-y = 27

y = -27

3 0

2 years ago