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zvonat [6]
3 years ago
10

Step 1: Configure the initial settings on R1. Note: If you have difficulty remembering the commands, refer to the content for th

is topic. The commands are the same as you configured on a switch. Open a configuration window a. Configure R1 as the hostname. b. Configure Message of the day text: Unauthorized
Computers and Technology
1 answer:
Andru [333]3 years ago
3 0

Answer:

The configuration of the R1 is as follows

Explanation:

Router>enable

Router#show running-config

Router#show startup-config

Router#configure terminal

Router(config)#hostname R1

R1(config)#line console 0

R1(config-line)#password letmein

R1(config-line)#login

R1(config-line)#exit

R1(config)#enable password cisco

R1(config)#enable secret itsasecret

R1(config)#service password-encryption

R1(config)#banner motd #Unauthorized access is strictly prohibited#

R1(config)#end

R1#exit

R1>enable

R1#copy running-config startup-config

R1#show flash

R1#copy startup-config flash

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Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

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       elif side1 == side2 or side1 == side3 or side2 == side3:

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else:

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Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

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If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

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<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

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Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

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clock_t start = clock();

int pos = biggest(arr,n);

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cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

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}

for(int x=0;x<result.size();x++)

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