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natka813 [3]
3 years ago
5

Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of z0 = 5i.

Mathematics
2 answers:
Zolol [24]3 years ago
5 0

Answer:

The three iterates are:

  • z_1=8i+3
  • z_2=14i+9
  • z_3=26i+21

Step-by-step explanation:

We are asked to find the first three iterates of the function:

f(z) =2z+(3-2i) with an initial value:

z_0=5i

The first iterate is:

z_1=f(z_0)=2z_0+(3-2i)\\\\z_1=2\times 5i+3-2i\\\\z_1=10i-2i+3\\\\z_1=8i+3

Now, the second iterate is:

z_2=f(z_1)=2z_1+(3-2i)\\\\z_2=2\times (8i+3)+3-2i\\\\z_2=16i+6+3-2i\\\\z_2=14i+9

Third iterate is:

z_3=f(z_2)=2z_2+(3-2i)\\\\z_3=2\times (14i+9)+3-2i\\\\z_3=28i+18+3-2i\\\\z_3=26i+21

Agata [3.3K]3 years ago
4 0
3 because the 2z minus the 3 gives you 1 rounded
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