Here's the picture, if anyone still needs it.
Given:
PQRS is a circle, PQT and SRT are straight lines.
To find:
The value of x.
Solution:
Since PQRS is a circle, PQT and SRT are straight lines, therefore, PQRS isa cyclic quadrilateral.
We know that, sum of opposite angles of a cyclic quadrilateral is 180 degrees.
Now, SRT is a straight line.
(Linear pair)
...(i)
According to the Exterior angle theorem, in a triangle the measure of an exterior angle is equal the sum of the opposite interior angles.
Using exterior angle theorem in triangle QRT, we get
Therefore, the value of x is 103 degrees.
Please see the attached graph to see f(x) = (x - 3) ^2 +5 graphed.
Answer:
H
Step-by-step explanation:
use slope of -2/3 and point (-4.5, 10) as input into the slope-intercept form of a line, which is y = mx + b
10 = -2/3(-9/2) + b
10 = 3 + b
7 = b
y = -2/3x + 7
Answer:
Step-by-step explanation:
B because did the same exact test