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QveST [7]
2 years ago
10

(5x-6) squared please answer​

Mathematics
2 answers:
Aleonysh [2.5K]2 years ago
7 0
Check photo for answer! i have included work

pashok25 [27]2 years ago
6 0

Answer:

25 x 2 − 60 x + 36

Step-by-step explanation:

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Find the vertex of y=-x^2-4x
Kay [80]
The vertex would be (-2,4)
3 0
3 years ago
A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid  

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

Volume=\frac{1}{2} (b_{1}+4+2x)h X H

Volume=\frac{1}{2} (4+4+2x)h X 16

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

V=64h+16h(\frac{h}{4})

V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}

h=3m,

dV/dt=25cm/min=0.25 m/min

0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0
3 years ago
Fiona and her friends are playing a game by guessing where a coin will land when it is randomly dropped inside the square shown
azamat

Answer:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The surface area of a ball is 3,600 square millimeters. What is the balls radius
allsm [11]
A = 4 \pi r^2

3600 = 4\pi r^2

\dfrac{3600}{4 \pi} = r^2

r^2 = 286.479

r = 16.9

Answer: The radius is 16.9 mm.
4 0
3 years ago
If Lin runs for 24 minutes at the same rate, how many laps does she run?
julia-pushkina [17]
About 21 hope I helped
7 0
2 years ago
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