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Strike441 [17]
3 years ago
13

Estimate the solution to the system of equations. asap, please!! I will mark for brain list

Mathematics
1 answer:
Darya [45]3 years ago
7 0

Answer:

(1 \frac{1}{3}, 2 \frac{1}{3} )

Step-by-step explanation:

Given the 2 equations

7x - y = 7 → (1)

x + 2y = 6 → (2)

Multiplying (1) by 2 and adding to (2) will eliminate the y- term

14x - 2y = 14 → (3)

Add (2) and (3) term by term to eliminate y

15x = 20 ( divide both sides by 15 )

x = \frac{20}{15} = \frac{4}{3} = 1 \frac{1}{3}

Substitute this value of x into either of the 2 equations and solve for y

Substituting in (2)

\frac{4}{3} + 2y = 6

2y = 6 - \frac{4}{3} = \frac{14}{3} ( divide both sides by 2 )

y = \frac{7}{3} = 2 \frac{1}{3}

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Write 500.2 in word form
Rainbow [258]

Answer:

Five hundred point two

Step-by-step explanation:

500.2

That's a deimal.

The digit 5 is an hundred. Hence, we have

Five hundred point two

7 0
3 years ago
The battery on McKenzies old computer can last 4(1/5) hours. She bought a new computer that has a battery that can last 40% long
Solnce55 [7]

Answer:

5\frac{22}{25}\ hours

Step-by-step explanation:

we know that

4\frac{1}{5}\ hours=\frac{4*5+1}{5}=\frac{21}{5}\ hours

100\%+40\%=140\%=\frac{140}{100}

Let

x ------> new battery life

The equation that represent this situation is

x=\frac{140}{100} (\frac{21}{5})=\frac{2,940}{500}\ hours

convert to mixed number

\frac{2,940}{500}=\frac{2,500}{500}+\frac{440}{500}=5\frac{22}{25}\ hours

4 0
3 years ago
Find the equation of a line passing through (3, -5) that is parallel to 2x+6y=10
Zina [86]

Answer:

The equation of the line would be y = -1/3x - 4

Step-by-step explanation:

In order to find this, we first need to find the slope of the original line. We do this by solving for y.

2x + 6y = 10

6y = -2x + 10

y = -1/3x + 5/3

Now that we see the slope as -1/3, we know the new line will have the same slope thanks to the definition of parallel lines. So, we can use this slope and the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - -5 = -1/3(x - 3)

y + 5 = -1/3x + 1

y = -1/3x - 4

4 0
3 years ago
Peter attends 6 lessons each week . A year he attends 52 weeks. But he missed 5 classes how many lessons did he attend during th
VMariaS [17]
You are given the information that he takes six lessons per week. First we will calculate the total lessons he could potentially take per year.

6 • 52 = 312

He could potentially take 312 lessons in one year.

Now that you know this information, you simply subtract the days he missed from that total.

312 - 5 = 307

Your final answer: Peter took 307 lessons during the year.
4 0
3 years ago
9a - ab + 5b<br><br>if a = 2 and b = 7​
Anit [1.1K]
9a-ab+5b
9(2)-(2)(7)+5(7)
18-14+35
39
8 0
2 years ago
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