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KIM [24]
3 years ago
7

How do I solve a quadratic functiona

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0
Quadratic Equation in Standard Form: ax2 + bx + c = 0.
Quadratic Equations can be factored.
Quadratic Formula: x = −b ± √(b2 − 4ac) 2a.
When the Discriminant (b2−4ac) is: positive, there are 2 real solutions. zero, there is one real solution. negative, there are 2 complex solutions.

HOPE THIS HELPS!!!
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Which statement about the equation is true?
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Infinitely many solutions, you need to do the distributive property.
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A squirrel burrowed 6 holes in 2 minutes. How many holes could the squirrel burrow in 7 minutes
irina [24]

Answer:

He burrows 6 holes in 2 minutes which means that he can burrow 3 holes in 1 minute.

To determine how many he can burrow in 7 minutes, you would multiply the

unit rate of 3 holes in 1 minute by 7.

He would burrow 21 holes in 7 minutes.

Step-by-step explanation:

brainliest pls?

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A restaurant charges $12.50 for 5 soft drinks. How much does the restaurant charge per soft drink?
djyliett [7]

Answer:

$2.50

Step-by-step explanation:

This problem is asking for the unit rate. To solve this problem, you would do $12.50 divided by 5 to get $2.50.

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What is the absolute value of 2.5
bixtya [17]

<em>☽------------❀-------------☾</em>

<em>Hi there!</em>

<em>~</em>

<em>The absolute value is the distance from 0 to 2.5. In this case the absolute value from 0 to |2.5| is 2.5 </em>

<em>❀Hope this helped you!❀</em>

<em>☽------------❀-------------☾</em>

7 0
3 years ago
An isosceles triangle with equal sides of 5 inches and a base of 6 inches is inscribed in a circle. What is the radius, in inche
lyudmila [28]

The radius of the circle is 3.12 inch.

<h3>What is isosceles triangle?</h3>

A triangle having two sides of equal length. Additionally equal are the angles that face the equal sides. Triangle of isosceles. Having two identical sides and angles.

Calculation for the radius of the circle;

Consider the isosceles triangle ABC inscribed in a a circle (attached figure)

Sides AB = AC = 5 inches.

Side BC = 6 inches.

Join OB, OC and OA.

Draw perpendicular on BC from AD which passes from the centre O.

OD bisects BC at point D.

So, BD = DC = 3 inches.

In the right angled triangle ABC

AB² = AD² + BD²

5² = AD² + 3²

AD² = 16

AD = 4 inches.

Let the radius of the circle be r.

Then, OB = OC = OA =  r

OD = AD - AO

OD = 4 - r

In the right angled triangle OBD;

OB² = OD² + BD²

r² = (4-r)² + 3³

On solving,

r = 25/8 = 3.12

Therefore, the radius of the circle comes out to be 3.12 inches.

To know more about the isosceles triangle, here

brainly.com/question/1475130

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1 year ago
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