Answer:
False
Step-by-step explanation:
please brainlist
Hi okay so if the original coords are a=(-2,0) b=(-3,-2) and c=(-5,-2), if one of the coords on the dilated triangle are (7,3), you apply that to the rest. so i think a=(7,3) b=(10.5,7) c=(17.5,7)but i’m not sure cause it says the constant is 4 but if you apply the constant of (7,3), the constant is -3.5. if you apple the constant of 4, the answers don’t really make sense.
answer: a=(7,3) b=(10.5,7) c=(17.5,7) i think
this question actually doesn’t really make sense at all. but i hope this helps lol.
1.5 is the answer to your question
9514 1404 393
Answer:
19.0 cm
Step-by-step explanation:
The length of each arc is given by ...
s = rθ
where r is the radius of the arc, and θ is its central angle in radians.
The sum of the two arc lengths is ...
s1 +s2 = (8 -4.5)(50(π/180)) +(8)(50(π/180)) = (16 -4.5)(5π/18) ≈ 10.0356
The sum of the two straight sides is ...
2·4.5 = 9.000
So, the perimeter is ...
P = arc lengths + straight sides = 10.0356 cm + 9.0000 cm ≈ 19.0 cm
This is so provided that the velocity changes continuously in which case we can apply the mean value theorem.
<span>Velocity (v) is the derivative of displacement (x) : </span>
<span>v = dx/dt </span>
<span>Monk 1 arrives after a time t* and Monk 2 too. </span>
<span>Name v1(t) and v2(t) their respective velocities throughout the trajectory. </span>
<span>Then we know that both average velocities were equal : </span>
<span>avg1 = avg2 </span>
<span>and avg = integral ( v(t) , t:0->t*) / t* </span>
<span>so </span>
<span>integral (v1(t), t:0->t*) = integral (v2(t), t:0->t*) </span>
<span>which is the same of saying that the covered distances after t* seconds are the same </span>
<span>=> integral (v1(t) - v2(t) , t:0->t*) = 0 </span>
<span>Thus, name v#(t) = v1(t) - v2(t) , then we obtain </span>
<span>=> integral ( v#(t) , t:0->t*) = 0 </span>
<span>Name the analytical integral of v#(t) = V(t) , then we have </span>
<span>=> V(t*) - V(0) = 0 </span>
<span>=> V(t*) = V(0) </span>
<span>So there exist a c in [0, t*] so that </span>
<span>V'(c) = (V(t*) - V(0)) / (t* - 0) (mean value theorem) </span>
<span>We know that V(0) = V(t*) = 0 (covered distances equal at the start and finish), so we get </span>
<span>V'(c) = v#(c) = v1(c) - v2(c) = 0 </span>
<span>=> v1(c) = v2(c) </span>
<span>So there exist a point c in [0, t*] so that the velocity of monk 1 equals that of monk 2. </span>