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3 years ago

How to find the are of each regular polygon

Mathematics

1 answer:

Ghella [55]3 years ago

7 0

Answer:

Hi there!

To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothem.

Apothem: a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.

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. Anne is pushing a wheelbarrow filled with mulch to place in her garden. She is pushing the wheelbarrow with a force of 70 N at

Kruka [31]

<u>Answer:</u>

When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules

<u>Solution:</u>

We know $\text { Work }(\mathrm{W})=\text { Force }(\mathrm{F})\times\text { Distance (D) }$

Anne is pushing the wheelbarrow with a force of 70 N at an angle of $50^{\circ}$ with the horizontal

So the force of Anne will be $F=70 \cos 50^{\circ}=(70 \times 0.64)=44.8 \mathrm{N}$

She pushes the wheelbarrow 25 meter, So D = 25 meters

So, the $work,F\times D=(44.8 \times 25)=1120 \text { Joules }$

Anne has done total 1120 joules work.

4 0

3 years ago

Metal A has a density of 12.7 g/cm3.

stira [4]

Using the given information, the density of metal B is 8.58 g/cm³

<h3>Calculating density </h3>

From the question, we are to determine the density of metal B

From the given information,

55 g of metal A is combined with metal B to create an alloy with mass 90 g

∴ Mass of metal B in the alloy = 90 g - 55 g = 35 g

Now, we will determine the volume of metal A in the alloy

Using the formula,

Density = Mass / Volume

∴ Volume = Mass / Density

Volume of metal A in the alloy = 55/12.7

Volume of metal A in the alloy = 4.33 cm³

Then, we will determine the volume of the alloy

Volume of the alloy = 90/10.7

Volume of the alloy = 8.41 cm³

∴ Volume of metal B in the alloy = 8.41 cm³- 4.33 cm³

Volume of metal B in the alloy = 4.08 cm³

Now, for the density of metal B

Density = mass / volume

Density of metal B = 35 / 4.08

Density of metal B = 8.58 g/cm³

Hence, the density of metal B is 8.58 g/cm³.

Learn more on Calculating density here: brainly.com/question/13986137

#SPJ1

5 0

2 years ago

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

4 0

3 years ago

Which problem situation matches the equation? -2 + 5 – 6 = X

mezya [45]

The answer is -9 for sure

8 0

2 years ago

What is the length of a hypotenuse when the legs are 5 and 12

Alisiya [41]

By using pythagoras theorem where
(Base)^2 +(perpedicular)^2 = (hypotenuse)^2
So,
(5)^2 +(12)^2 = (hypotenuse)^2
25 + 144 = (hypotenuse)^2
169 = (hypotenuse)^2
13 = hypotenuse

So, hypotenuse = 13

8 0

3 years ago