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3 years ago

What is the area a a circle when the circumference is 3.50

Mathematics

1 answer:

Lapatulllka [165]3 years ago

6 0

The area of the circle would be 0.97

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What is the x intercept of -6x-3y=18?

damaskus [11]

-6x-3y=18
Substitute 0 for y
-6x-3(0)=18
Multply -3 by 0
-6x=18
Divide both sides by -6 so that the only thing on the left side is the variable x.
Final Answer: x= -3

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3 years ago

Choose the equation for the relationship shown in the graph.

uysha [10]

Answer:

B) y = x - 50

Step-by-step explanation:

It is B because the graph's y-intercept lies on the point (0, -50), hence the equation, y = x - 50. In addition, you can verify that B is the correct answer because the slope of the graph is positive, and so the x-value also must be positive.

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2 years ago

The revenue from selling x units of a product at a price of p dollars per unit is given by xp, For a particular commodity, the r

marshall27 [118]

> Factor the expression for the revenue

We are given that the revenue is the product of price and number of units sold = x p. Given the equation of revenue we factor it:

R = 800 x – 0.25 x^2

Take out x from the equation:

R = x (800 – 0.25 x)

We see that this is now in the form x p

> Determine an expression for the price in terms of x

From the factored equation we can say that the price in terms of x is:

p = 800 – 0.25 x

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4 years ago

Rotation: 90° cow about the origin

ryzh [129]

Answer:

im not sure

Step-by-step explanation:

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3 years ago

Please help me with this question

BartSMP [9]

Answer:

$3x-28=2x+25\\x=53$

Step-by-step explanation:

Parallel lines cut by a transversal are two lines which do not cross intersected by a third line. Because lines such as m and n are parallel, we have angles which are equal to each other.

Corresponding Angles - angles located in the same position in each intersection. Can be shown by translating or sliding the angle down/up.
Alternate Interior Angles - angles located inside the parallel lines across the transversal. Can be shown by reflecting and translating or rotation.
Alternate Exterior Angles - angles located outside the parallel lines across the transversal. Can be shown by reflecting and translating or rotation.

Vertical angles - angles across a vertex from one another. Can be shown by reflection.

The angles shown here are located outside the parallel lines and across the transversal from each other. Therefore we have Alternate Exteroir angles and can set them equal to each other to solve for x.

$3x-28=2x+25\\3x-2x-28=2x-2x+25\\x-28=25\\x-28+28=25+28\\x=53$

We check our work and should get equal angles:

$3(53)-28=2(53)+25\\159-28=106+25\\131=131$

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3 years ago