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asambeis [7]
3 years ago
5

What is the value of n in this equation?n+ 134 = 379423245334​

Mathematics
2 answers:
alexira [117]3 years ago
5 0

Answer:

the answer to this question is 245

Step-by-step explanation:

n+134=379

-134 -134

n=245

balu736 [363]3 years ago
5 0

Answer:

n=379423245234

Step-by-step explanation:

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Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and
grigory [225]

Answer:

The correct option is:

Building B; it is around 16.35 feet taller than building A.

Step-by-step explanation:

Consult the diagram below where the first figure represent building A and second figure represents building B

For building A:

tan θ = Perpendicular / Base

tan 73° = Height of building A / 30

Height of building A = tan73 · 30

Height of building A = 98.13 ft

For building B:

tan θ = Perpendicular / Base

tan 73° = Height of building B / 35

Height of building A = tan73 · 35

Height of building A = 114.48 ft

Building B is taller

Difference in height = height of building B - height of building A

Difference in height = 114.48 - 98.13 = 116.35 feet

3 0
3 years ago
Suppose that Clayton Kershaw of the Los Angeles Dodgers throws his fastball with a mean velocity of 94 miles per hour (mph) and
vekshin1

Answer:

Step-by-step explanation:

ah,  probability,  so the std. deviation is 2 MPH,  so that means to get from the mean.. or average speed of 94, he'll have to vary by 3 std. deviations  or  6 MPH to hit 100

99.7%  of throws fall into that area of with in 3 std. deviations so that means

0.3% fall outside also , 1/2 of those will 3 std. deviations slow while the other half is fast

so

0.15%  will be 100 or faster.... not many

8 0
2 years ago
X2 – 1x – 90 = 0 has solutions {a, b}. What is a + b?
s344n2d4d5 [400]

Answer:

a + b =1

Step-by-step explanation:

Write the given quadratic as x^2 – 1x – 90 = 0.  This factors into

(x - 10)(x + 9) = 0, and so the roots/solutions are {-9, 10}.

If we call -9 "a" and 10 "b," then the sum a + b is -9 + 10, or a + b =1.

3 0
3 years ago
The weight of a product is normally distributed with a mean of four ounces and a variance of .25 squared ounces. What is the pro
ololo11 [35]

Answer:

P(X>3.75)=P(\frac{X-\mu}{\sigma}>\frac{3.75-\mu}{\sigma})=P(Z>\frac{3.75-4}{0.5})=P(z>-0.5)

And we can find this probability using the complement rule and we got:

P(z>-0.5)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(4,\sqrt{0.25}=0.5)  

Where \mu=4 and \sigma=0.5

We are interested on this probability

P(X>3.75)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>3.75)=P(\frac{X-\mu}{\sigma}>\frac{3.75-\mu}{\sigma})=P(Z>\frac{3.75-4}{0.5})=P(z>-0.5)

And we can find this probability using the complement rule and we got:

P(z>-0.5)=1-P(z

5 0
3 years ago
the probability density for a particle in a box is an oscillatory function even for very large energies. Explain how the classic
77julia77 [94]

Answer:

This is achieved for the specific case when high quantum number with low resolution is present.

Step-by-step explanation:

In Quantum Mechanics, the probability density defines the region in which the  likelihood of finding the particle is most.

Now for the particle in the box, the probability density is also dependent on resolution as well so for large quantum number with small resolution, the oscillations will be densely packed and thus indicating in the formation of a constant probability density throughout similar to that of classical approach.

8 0
3 years ago
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