How to solve y=-8x,2x+4y=0

1 answer:

6 0

Answer:

$x=0$

Step-by-step explanation:

$\text{Replace } [-8x] \text{ for } [y]\\\rightarrow [2x+4(-8x)=0]\\\\\text{Solve}\\[2x-32x=0]\\[-30x=0]\\= [0]$

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