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nirvana33 [79]
3 years ago
7

How to solve y=-8x,2x+4y=0

Mathematics
1 answer:
vovikov84 [41]3 years ago
6 0

Answer:

x=0

Step-by-step explanation:

\text{Replace } [-8x] \text{ for } [y]\\\rightarrow [2x+4(-8x)=0]\\\\\text{Solve}\\[2x-32x=0]\\[-30x=0]\\= [0]

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Given sin theta=1/3 and 0 < theta< π/2; find tan 2 theta.
mote1985 [20]

Answer:

tan2θ = 4√2/7

Step-by-step explanation:

Given sin theta=1/3 and 0 < theta< π/+

Required

tan 2 theta

tan2 theta = 2tanθ/1-tan²θ

Get tan θ

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adj = √3²-1²²

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Rationalize

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6 0
2 years ago
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Tju [1.3M]

Answer:

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Step-by-step explanation:

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