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3 years ago

Please help guys!! I’ll mark you as brainlyest!!

Mathematics

1 answer:

fgiga [73]3 years ago

6 0

Answer:

138

Step-by-step explanation:

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Need help with this asap!

My name is Ann [436]

Answer:

Step-by-step explanation:

1 ) 2 + 7t [ there are no like terms , so no further simplifying ]

2) 6r + ( - 16 r )

= 6 r - 16 r [ both are like terms ]

= - 10 r

3) (3x + 2 ) + ( 2x - 4 )

= 3x + 2 + 2x - 4

= 3x + 2x - 4 + 2 [ arranging like terms together ]

= 5x - 2

4) (8 n² - 3 n + 6 ) + ( n - 2 )

= 8n² - 3n + 6 + n - 2

= 8n² - 3n + n + 6 - 2 [ bringing like terms together ]

= 8n² - 2n + 4

6 0

2 years ago

Read 2 more answers

What is 588 times 7 588x7

motikmotik

4116 hope this answer help

3 0

2 years ago

There are 10 marbles in a bag. Four are blue, 3 are black and 2 white and 1 red. If the marbles are not replaced once they are d

stich3 [128]

Given:

Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.

The marbles are selected by not replacing the drawn ones.

We need to the probability of selected a black marble and then a white marble without replacement.

Probability:

Let B denote the black marble.

Let W denote the white marble.

The probability of selecting a black marble is $P(B)=\frac{3}{10}$

The probability of selecting a white marble without replacement is $P(W)=\frac{2}{9}$

The probability of selecting a black marble and then a white marble without replacement is given by

$P(B \ and \ W)=P(B) \cdot P(W)$

Substituting the values, we get;

$P(B \ and \ W)=\frac{3}{10} \cdot \frac{2}{9}$

$P(B \ and \ W)=\frac{6}{90}$

$P(B \ and \ W)=\frac{1}{15}$

Thus, the probability of selecting a black marble and then a white marble without replacement is $\frac{1}{15}$

4 0

3 years ago

What is the range of 98, 13,41,62 and 8

jonny [76]

The range of it is 90 subtract the greatest # from the least 90-8

4 0

2 years ago

k0ka [10]

Answer:

C) the length of DG and JL

4 0

2 years ago