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3 years ago

Please help me out with this!!!!!!!!!!!!

Mathematics

1 answer:

vesna_86 [32]3 years ago

6 0

Answer:

y = - $\frac{3}{4}$ x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (4, 0) ← 2points on the line

m = $\frac{0-3}{4-0}$ = - $\frac{3}{4}$

Note the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = - $\frac{3}{4}$ x + 3 ← equation of line

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SOMEBODLY PLZ HELP ASAP! Find x

antoniya [11.8K]

Answer:

x=4

Step-by-step explanation:

We can use the leg rule

hyp leg

------- = -----------------

leg part

2+6 x

------- = -----------------

x 2

Using cross products

8*2 = x^2

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4 0

2 years ago

Read 2 more answers

Mary takes a sightseeing tour on a helicopter that can fly 450 miles against a 35 mph headwind. In the same amount of time it ca

monitta

Answer:

V = 160mph

Step-by-step explanation:

We need to start from the formula of speed: V=d/t

We have two travels, with and against the wind, both done in the same time.

Clearing t from the formula, we will have: t=d/V2

450miles/V-35mph (speed of the wind is subtracted)

702miles/V+35mph (speed of the wind is subtracted)

Now, we find V:

450miles/V-35mph = 702miles/V+35

450*V+35 = 702*V-35

450V+15,750 = 702V-24,570

702V-450V = 15,750 + 24,570

252V = 40,320

V = 40,320/252

V = 160mph

5 0

3 years ago

Find an equation of the line through these points (15,2.2) (5,1.6). Write answer in a slope-intercept form

nadya68 [22]

Answer:

$y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where $m$ is the slope and $b$ is the y-intercept (the value of y when x is 0)

1) Determine the slope (m)

$m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}$ where two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (15,2.2) and (5,1.6):

$m=\frac{\displaystyle 1.6-2.2}{\displaystyle 5-15}\\\\m=\frac{\displaystyle -0.6}{\displaystyle -10}\\\\m=\frac{\displaystyle 0.6}{\displaystyle 10}\\\\m=\frac{\displaystyle 0.3}{\displaystyle 5}\\\\m=\frac{\displaystyle 3}{\displaystyle 50}$

Therefore, the slope of the line is $\frac{\displaystyle 3}{\displaystyle 50}$ . Plug this into $y=mx+b$ :

$y=\frac{\displaystyle 3}{\displaystyle 50}x+b$

2) Determine the y-intercept (b)

$y=\frac{\displaystyle 3}{\displaystyle 50}x+b$

Plug in a given point and solve for b:

$1.6=\frac{\displaystyle 3}{\displaystyle 50}(5)+b\\\\1.6=\frac{\displaystyle 3}{\displaystyle 10}+b\\\\1.6-\frac{\displaystyle 3}{\displaystyle 10}=\frac{\displaystyle 3}{\displaystyle 10}+b-\frac{\displaystyle 3}{\displaystyle 10}\\\\\frac{\displaystyle 13}{\displaystyle 10}=b$