Marine magnetic anomalies result from seafloor spreading in conjunction with

Help Why does the sun move around the Milky Way galaxy

AnnyKZ [126]

It doesn't the sun stays still we move around the sun

5 0

3 years ago

In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac

Elan Coil [88]

Answer:

$a=0.284\ m/s^2$

Explanation:

Given that,

Initially, the spaceship was at rest, u = 0

Final velocity of the spaceship, v = 11 m/s

Distance accelerated by the spaceship, d = 213 m

We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2$

So, the acceleration experienced by the occupants of the spaceship is $0.284\ m/s^2$ .

5 0

3 years ago

The supercontinent in the continental drift hypothesis was called

Oksanka [162]

Answer:

Pangaea

Explanation:

The Earth's crust is not one solid block but is made of different segments called tectonic plates. At one point it started to break apart. The land mass was present around the Paleozoic and Mesozoic eras. This land mass was called Pangaea

As a result all the water on Earth was a part of an ocean called Panthalassa. The concept of the one land mass and one water mass was proposed be Alfred Wagner.

Hence, the statement here is referring to Pangaea.

8 0

3 years ago

A 0.145 kg baseball is flying at a height of 2.50 m. How much potential energy

Studentka2010 [4]

Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:

$\boxed{U_g=W\cdot h=mgh}$

Where:

W is the weight of the object
m is the mass
g is gravitational acceleration
h is the height

Evaluating:

$U_g = (0.145\;kg)(9.8\;m/s^2)(2.50\;m)\\\\\boxed{U_g=3.5525\;J}$

R/ The ball has 3.5525 J of potential energy.

3 0

3 years ago

Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, i

Virty [35]

Answer:

J=600 kg m/s

Explanation:

Impulse And Momentum

Suppose a particle is moving at a certain speed $v_1$ and changes it to $v_2$ . The impulse J is equivalent to the change of linear momentum. The momentum can be computed by