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3 years ago

What is the impulse of a 1700 kg truck traveling at 22.5 m/s?

1 answer:

3 0

Impulse is just the product of mass and speed!

I = 1700 * 22.5 = 38,250 kg m/s

It does not have any special name for its units :(

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In an RC series circuit, ε = 12.0 V, R = 1.25 MΩ, and C = 1.42 µF. (a) Calculate the time constant. (b) Find the maximum charge

faust18 [17]

Answer:

a, 1.775s

b, 17.04μC

c, 1.28s

Explanation:

Given

R = 1.25MΩ

C = 1.42µF

ε = 12.0 V

q = 8.78 µC

Time constant, τ = RC

τ = (1.25*10^6) * ( 1.42*10^-6)

τ = 1.775s

q• = εC

q• = 12 * 1.42*10^-6

q• = 17.04*10^-6C

q• = 17.04μC

Time t =

q = q• [1 - e^(t/τ)]

t = τIn[q•/(q•-q)]

t = 1.775In[17.04μC/(17.04μC-8.78μC)]

t = 1.775In(2.06)

t = 1.775*0.723

t = 1.28s

8 0

3 years ago

How many total atoms are in one molecule of lithium nitrate, LiNO3? 1 3 5 7 6

Zanzabum

There are 5 atoms 1=LI 1=N 3=O

7 0

3 years ago

Read 2 more answers

If it takes 150N of force to move a box 10 meters. what is the work done on the box?

sergeinik [125]

Answer:

1500 Joules

Explanation:

Work = Force x Distance

When multiplying by 10 you simply shift all the digits to the

left and append a 0 to the end.

so 150 x 10 = 1500 Joules

3 0

3 years ago

Read 2 more answers

What is an example of a non contact force

olchik [2.2K]

Answer: Gravitational force

Explanation:

A non contact force can be described as a force applied to an object by another body that is not in direct contact with it.

For example, an object thrown upwards will return back due to the force of gravity acting on it. So, it means Gravitational force is acting on the body without necessarily being in contact with that body.

8 0

3 years ago

The starships of the Solar Federation are marked with the symbol of the Federation, a circle, whereas starships of the Denebian

Llana [10]

Complete question

The complete question is shown on the first uploaded image

Answer:

The velocity is $v = c* \sqrt{1 - \frac{1}{n^2} }$

Explanation:

From the question we are told that

a = nb

The length of the minor axis of the symbol of the Federation, a circle, seen by the observer at velocity v must be equal to the minor axis(b) of the Empire's symbol, (an ellipse)

Now this length seen by the observer can be mathematically represented as

$h = t \sqrt{1 - \frac{v^2}{c^2} }$

Here t is the actual length of the major axis of of the Empire's symbol, (an ellipse)

So t = a = nb

and b is the length of the minor axis of the symbol of the Federation, (a circle) when seen by an observer at velocity v which from the question must be the length of the minor axis of the of the Empire's symbol, (an ellipse)

i.e h = b

$b = nb [\sqrt{1 - \frac{v^2}{c^2} } ]$

$[\frac{1}{n} ]^2 = 1 - \frac{v^2}{c^2}$

$v^2 =c^2 [1- \frac{1}{n^2} ]$

$v^2 =c^2 [\frac{n^2 -1}{n^2} ]$

$v = c* \sqrt{1 - \frac{1}{n^2} }$

6 0

3 years ago