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Alexxx [7]
3 years ago
15

In equation y = mx means what

Physics
1 answer:
andrew11 [14]3 years ago
8 0
The slope is the number "m" that is multiplied on the x, and "b" (seems that you forgot to write it) is the y-intercept
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Shock best describes the current model of the atom ?
const2013 [10]

Answer:

IDK?//

Explanation:

8 0
3 years ago
Write answers with significant figures:<br>a) 17.35 g +8.498 g​
Genrish500 [490]

Answer:

25.9 g

Explanation:

= 17.35

8.498

________+

= 25.848 g = 25.85 g = 25.9 g

*so sorry if wrong

6 0
3 years ago
In which collision scenario is the difference in total momentum before and total momentum after the collision the greatest?
Hitman42 [59]

Answer:

The law states that when two objects collide in a closed system, the total momentum of the two objects before the collision is the same as the total momentum of the two objects after the collision. The momentum of each object may change, but the total momentum must remain the same.

Explanation:

8 0
2 years ago
a 2.0 kg hoop rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear spe
e-lub [12.9K]

Answer:

72 J

Explanation:

Total kinetic energy will be tge sum of rotational and translational energy.

Rotational kinetic energy is given by 0.5I\omega^{2} where I is moment of inertia which is given by mr^{2} and here m is mass, r is radius. Also, v=\omega r hence making \omega the subject then \omega=\frac {v}{r} where v is the velocity.

Rotational kinetic energy=0.5I\omega^{2}=0.5mr^{2}\times(\frac {v}{r})^{2}= 0.5mv^{2}

This is same as the formula for translational kinetic energy which is given by 0.5mv^{2}

Therefore, total kinetic energy= 0.5mv^{2}+0.5mv^{2}=mv^{2}

Substituting m with 2 kg and v with 6 m/s then total energy will be 2\times 6^{2}=72 J

7 0
3 years ago
A 24-cm-diameter vertical cylinder is sealed at the top by a frictionless 15 kg piston. The piston is 90 cm above the bottom whe
abruzzese [7]

Answer:

(A) P_i=3249.41\ Pa

(B) V_f=0.3358\ m

Explanation:

Given:

  • diameter of the cylinder, d= 0.24\ m
  • mass of piston sealing on the top, m_p=15\ kg
  • initial temperature of the piston, T_i=315+273= 588\ K
  • initial height of piston, h_i=0.9\ m
  • atmospheric pressure on the piston, p_a=1 atm=101325\ Pa

(A)

<u>Initial pressure of gas is the pressure balanced by the weight of piston:</u>

P_i=\frac{m_p.g}{\pi.d^2\div 4}

P_i=\frac{15\times 9.8}{\pi\times (0.24^2\div 4)}

P_i=3249.41\ Pa

<em>Which is gauge pressure because it is measured with respect to the atmospheric pressure.</em>

(B)

Given:

  • Final temperature, T_f=18+273=291\ K

<u>Now, volume of air initially in the cylinder:</u>

V_i=\pi.d.h_i

V_i=\pi\times 0.24\times 0.9

V_i=0.6786\ m^3

Using gas law:

\frac{P_i V_i}{T_i}= \frac{P_f V_f}{T_f} ........................................(1)

<em>∵In every condition of equilibrium the gas pressure will be balanced by the weight of the piston so it is an </em><em>isobaric transition</em><em>.</em>

∴P_i=P_f

<u>Hence eq. (1) is reduced to:</u>

\frac{V_i}{T_i}= \frac{V_f}{T_f}

putting respective values:

\frac{0.6786}{588}= \frac{V_f}{291}

V_f=0.3358\ m

6 0
4 years ago
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