Answer:
Givens
![m \angle BAC=63\°](https://tex.z-dn.net/?f=m%20%5Cangle%20BAC%3D63%5C%C2%B0)
![m(BE)=96\°](https://tex.z-dn.net/?f=m%28BE%29%3D96%5C%C2%B0)
is secant.
is tangent.
<h3>(A)</h3>
Remember that the arc subtended by a central angle is equal to it. That means
![m(BC)=m\angle BAC = 63\°](https://tex.z-dn.net/?f=m%28BC%29%3Dm%5Cangle%20BAC%20%3D%2063%5C%C2%B0)
<h3>(B)</h3>
Now, by sum of arcs, we know
![m(EBC)=m(EB)+m(BC)=96\° +63\°=159\°](https://tex.z-dn.net/?f=m%28EBC%29%3Dm%28EB%29%2Bm%28BC%29%3D96%5C%C2%B0%20%2B63%5C%C2%B0%3D159%5C%C2%B0)
<h3>(C)</h3>
By definition, the total arc of a circle is 360°, so
![m(EFC)=360\°-m(EBC)=360\° - 159\°=201\°](https://tex.z-dn.net/?f=m%28EFC%29%3D360%5C%C2%B0-m%28EBC%29%3D360%5C%C2%B0%20-%20159%5C%C2%B0%3D201%5C%C2%B0)
<h3>(D)</h3>
We know that the external angle formed by a secant and a tanget is one half of the difference between the intercepted arcs, so
![\angle D=\frac{1}{2}(m(EFC)-m(BC))=\frac{1}{2} (201\° - 63\°)=\frac{1}{2} (138\°)=69\°](https://tex.z-dn.net/?f=%5Cangle%20D%3D%5Cfrac%7B1%7D%7B2%7D%28m%28EFC%29-m%28BC%29%29%3D%5Cfrac%7B1%7D%7B2%7D%20%28201%5C%C2%B0%20-%2063%5C%C2%B0%29%3D%5Cfrac%7B1%7D%7B2%7D%20%28138%5C%C2%B0%29%3D69%5C%C2%B0)
So, the angle D is 69°.
Answer:
x=−7/8
Step-by-step explanation:
Answer:
(-∞,∞)
B) x cannot equal -4, 2
Step-by-step Explanation:
The function, y = x + 2, has a domain of (-∞,∞) because the equation will remain true no matter number you plug for x.
For the second question, x would be equal to -2 and 4. You can find this by factoring the equation. x² + 2x - 8 = (x - 2)(x + 4) Your answer should be B
Well 5 is ones
9 is tenths
2 is hundredths
3 is thousandths
so 3 is the answer