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forsale [732]
3 years ago
14

What is 1/3 + 3/91/3 + 3/9=?

Mathematics
2 answers:
Alecsey [184]3 years ago
5 0
1/3 + 3/9 =
Answer: 2/3
atroni [7]3 years ago
4 0

Answer:2/3

Step-by-step explanation:

3/9=1/3

1/3+1/3=2/3

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How many cupcakes can I make with 16 cups of batter if I pour 2/3 Cup of batter into each cake?
klasskru [66]

Answer:

Step-by-step explanation:

16×2/3

32/3

104

5 0
3 years ago
How many ways can 100 be written as the sum of distinct integers from the set {1, 2,..., 15}?
konstantin123 [22]

Answer:

48 ways

Step-by-step explanation:

Let me take a guess

S₁_₁₅ = (1+15)*7 + 8 = 120

There are 48 combinations of distinct digits from 1 to 15 to make 20

120-20=100

So every 20 has a corresponding 100

I wish I got it right, otherwise report it.

4 0
3 years ago
A recent survey found that 70% of all adults over 50 wear
lubasha [3.4K]

Answer:

There is an 84.97% probability that at least six wear glasses.

Step-by-step explanation:

For each adult over 50, there are only two possible outcomes. Either they wear glasses, or they do not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 10, p = 0.7

What is the probability that at least six wear glasses?

P(X \geq 6) = P(X = 6) + `P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.8497

There is an 84.97% probability that at least six wear glasses.

5 0
3 years ago
What is (57/tan30°)m^2
iVinArrow [24]
57\sqrt{3}m^2. Enjoy!
6 0
3 years ago
You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w
Margaret [11]

Answer:

a

  The null hypothesis is  

         H_o  : \mu  =  21

The Alternative  hypothesis is  

           H_a  :  \mu<   21

b

     \sigma_{\= x} =   0.8944

c

   t = -2.236

d

  Yes the  mean population is  significantly less than 21.

Step-by-step explanation:

From the question we are given

           a set of  data  

                               20  18  17  22  18

       The confidence level is 90%

       The  sample  size  is  n =  5  

Generally the mean of the sample  is  mathematically evaluated as

        \= x  =  \frac{20 + 18 +  17 +  22 +  18}{5}

       \= x  =  19

The standard deviation is evaluated as

        \sigma =  \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }

         \sigma =  \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }

         \sigma = 2

Now the confidence level is given as  90 %  hence the level of significance can be evaluated as

         \alpha = 100 - 90

        \alpha = 10%

         \alpha =0.10

Now the null hypothesis is  

         H_o  : \mu  =  21

the Alternative  hypothesis is  

           H_a  :  \mu<   21

The  standard error of mean is mathematically evaluated as

         \sigma_{\= x} =   \frac{\sigma}{ \sqrt{n} }

substituting values

         \sigma_{\= x} =   \frac{2}{ \sqrt{5 } }

        \sigma_{\= x} =   0.8944

The test statistic is  evaluated as  

              t =  \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }

substituting values

              t =  \frac{ 19  - 21 }{ 0.8944 }

              t = -2.236

The  critical value of the level of significance is  obtained from the critical value table for z values as  

                   z_{0.10} =  1.28

Looking at the obtained value we see that z_{0.10} is greater than the test statistics value so the null hypothesis is rejected

6 0
3 years ago
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