Answer: 1.96 m/s
Explanation:
Given
Mass of Professor ![m_1=113\ kg](https://tex.z-dn.net/?f=m_1%3D113%5C%20kg)
Velocity of professor ![u_1=1.56\ m/s](https://tex.z-dn.net/?f=u_1%3D1.56%5C%20m%2Fs)
mass of chair ![m_2=10\ kg](https://tex.z-dn.net/?f=m_2%3D10%5C%20kg)
velocity of chair ![u_2=6.5\ m/s](https://tex.z-dn.net/?f=u_2%3D6.5%5C%20m%2Fs)
Suppose after the collision, v is the common velocity
Conserving momentum
![\Rightarrow m_1u_1+m_2u_2=(m_1+m_2)v\\\\\Rightarrow v=\dfrac{113\times 1.56+10\times 6.5}{113+10}=\dfrac{241.28}{123}\\\\\Rightarrow v=1.96\ m/s](https://tex.z-dn.net/?f=%5CRightarrow%20m_1u_1%2Bm_2u_2%3D%28m_1%2Bm_2%29v%5C%5C%5C%5C%5CRightarrow%20v%3D%5Cdfrac%7B113%5Ctimes%201.56%2B10%5Ctimes%206.5%7D%7B113%2B10%7D%3D%5Cdfrac%7B241.28%7D%7B123%7D%5C%5C%5C%5C%5CRightarrow%20v%3D1.96%5C%20m%2Fs)
Answer
A. Half elementary charge
Explanation:
Answer:
The magnitude of the vector A is <u>51 m.</u>
Explanation:
Given:
The horizontal component of a vector A is given as:
![A_x=44.4\ m](https://tex.z-dn.net/?f=A_x%3D44.4%5C%20m)
The vertical component of a vector A is given as:
![A_y=25.1\ m](https://tex.z-dn.net/?f=A_y%3D25.1%5C%20m)
Now, we know that, a vector A can be resolved into two mutually perpendicular components; one along the x axis and the other along the y axis. The magnitude of the vector A can be written as the square root of the sum of the squares of each component.
Therefore, the magnitude of vector A is given as:
![|\overrightarrow A|=\sqrt{A_{x}^2+A_{y}^2}](https://tex.z-dn.net/?f=%7C%5Coverrightarrow%20A%7C%3D%5Csqrt%7BA_%7Bx%7D%5E2%2BA_%7By%7D%5E2%7D)
Now, plug in 44.4 for
, 25.1 for
and solve for the magnitude of A. This gives,
![|\overrightarrow A|=\sqrt{(44.4)^2+(25.1)^2}\\|\overrightarrow A|=\sqrt{1971.36+630.01}\\|\overrightarrow A|=\sqrt{2601.37}\\|\overrightarrow A|=51\ m](https://tex.z-dn.net/?f=%7C%5Coverrightarrow%20A%7C%3D%5Csqrt%7B%2844.4%29%5E2%2B%2825.1%29%5E2%7D%5C%5C%7C%5Coverrightarrow%20A%7C%3D%5Csqrt%7B1971.36%2B630.01%7D%5C%5C%7C%5Coverrightarrow%20A%7C%3D%5Csqrt%7B2601.37%7D%5C%5C%7C%5Coverrightarrow%20A%7C%3D51%5C%20m)
Therefore, the magnitude of the vector A is 51 m.
Answer:
300 m
Explanation:
The ball moves with constant velocity, so the distance it covers is given by:
![d=vt](https://tex.z-dn.net/?f=d%3Dvt)
where
v=6 m/s is the ball's velocity
t=50 s is the time
Substituting these numbers into the equation, we find
![d=(6 m/s)(50 s)=300 m](https://tex.z-dn.net/?f=d%3D%286%20m%2Fs%29%2850%20s%29%3D300%20m)
Answer:Most likely yes, sorry if wrong!!
Explanation: