The displacement of Edward in the westerly direction is determined as 338.32 km.
<h3>What is displacement of Edward?</h3>
The displacement of Edward can be determined from different methods of vector addition. The method applied here is triangular method.
The angle between the 200 km north west and 150 km west = 60 + 90 = 150⁰
The displacement is the side of the triangle facing 150⁰ = R
R² = a² + b² - 2abcosR
R² = 150² + 200² - (2x 150 x 200)xcos(150)
R² = 62,500 - (-51,961.52)
R² = 114,461.52
R = 338.32 km
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1.6 m/s west is the answer
The formula for acceleration is a = F/m; Where: F = force; m = mass
Given: F = .6n; m = .4kg; a = ?
a = F/m
= .6/.4
= 1.5
Therefore, the acceleration of the plate is 1.5 m/s^2
careful observation, curiosity, logic, creativity, skepticism, and objectivity
Answer:
14.36 N
Explanation:
= Tension in string 1
= Tension in string 2
= mass of the bar = 2.7 kg
= weight of the bar
weight of the bar is given as
N
= mass of the bar = 1.35 kg
= weight of the monkey
weight of the monkey is given as
N
Using equilibrium of torque about left end
N
Using equilibrium of force in vertical direction
N
