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Viefleur [7K]
3 years ago
15

A song is playing on a radio. Which of the following best

Physics
2 answers:
PtichkaEL [24]3 years ago
6 0
One is the best choice for an answer.
Aneli [31]3 years ago
6 0
A: electrical energy is changed to sound energy.
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Potential energy is directly proportional to height.  Double the height, you double the potential energy.
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Select all that apply.
sattari [20]

Answer: The temperature and the number of molecules must remain constant for the law to apply.

Explanation:

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The earth completes one _______ when it travels once around the sun.
zlopas [31]

Answer: Revolution

Explanation:

The Earth rotates about its axis in 23 hours 56 minutes i.e. in one day. The Earth revolves around the Sun in one year (365 and 6 hours). Axis is an imaginary line passing through the center of any body about which it rotates. Solstice is an event when Sun is passing over Tropic of Capricorn or Tropic of cancer.

Hence, the correct option is The earth completes one <u>Revolution</u> when it travels once around the sun.

4 0
3 years ago
A ball rolls 60 centimeters along a sidewalk in 5 seconds what is the speed of the ball.
meriva

Answer:

12 cm/s

Explanation:

Quite simply, you are looking for  cm/s

  so   60 cm / 5s   = 12 cm/s

6 0
2 years ago
Read 2 more answers
50. A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 335 kV. The secondar
Sedaia [141]

Answer:

Explanation:

a )  The transformer steps  up  the voltage from 12000 V  to 335000 V . Voltage in primary is 12000 V and in the secondary it is 335000 V in old transformer

If n₁ be no of turns in primary coil and n₂ be no of turns in secondary coils

the formula is

n₂ / n₁ = voltage in secondry / voltage in primary

n₂ / n₁ = 335000 / 12000

ratio of turns  in old transformer

= 27.9

ratio of turns  in new transformer

n₃ / n₁ = 750 / 12 ( n₃ is no of turns in the  secondary of new transformer )

= 62.5

T he ratio of turns in the new secondary compared with the old secondary

n₃ / n₂ = 62.5 / 27.9

= 2.24

b ) Current in secondary / current in primary

= turns in primary / turns in secondary

current output ratio of old

= Current in secondary / current in primary

= n₁ / n₂

= 12 / 335

= .03582

current output ratio of new

= Current in secondary / current in primary

= n₁ / n₃

= 12 / 750  

= .016

The ratio of new current output to old output (at 335 kV) for the same power

= .016 / .03582

= .4466

c ) power loss in new

=  (current in secondary )² x resistance of secondary

=( .016 x current in primary )² x R

= 2.56 X 10⁻⁴ X ( current in primary )² x R

power loss in old  

=  (current in secondary )² x resistance of secondary

=( .03582 x current in primary )² x R

= 12.83 X 10⁻⁴ X ( current in primary )² x R

ratio of new line power loss to old

= 2.56 / 12.83

= .199

7 0
3 years ago
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