Question

The temperature in a pressure cooker is 130 degree C while the water is boiling. Determine the pressure inside the cooker.

Answer 1

Answer:

The pressure inside the cooker is 1.0804 atm.

Explanation:

Boiling occurs when the vapor pressure becomes equal to atmospheric pressure.

For water, At standard conditions (Pressure = 1 atm) boiling occurs at 373.15 K.

So, Standard conditions:

T₁ = 373.15 K

P₁ = 1 atm

Given ,

The water boils at Temperature =  130 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So, the temperature, T₂ = (130 + 273.15) K = 403.15 K

To find pressure inside the cooker (P₂) :

Applying Amontons's Law as:

$\frac {P_1}{T_1}=\frac {P_2}{T_2}$

So,

$P_2=\frac {P_1}{T_1} \times {T_2}$

$P_2=\frac {1 atm}{373.15 K} \times {403.15 K}$

$P_2=1.0804 atm$

Thus, The pressure inside the cooker is 1.0804 atm.