Answer:
The first one A, " These are lines of equal air pressure".
Explanation:
Times the radius squared !
hope this helps :)))
Answer:
The flow velocity reduces to 0.72 m/s
Explanation:
According to the equation of continuity discharge in the channel should remain same
Thus we have
![A_{1}V_{1}=A_{2}V_{2}](https://tex.z-dn.net/?f=A_%7B1%7DV_%7B1%7D%3DA_%7B2%7DV_%7B2%7D)
For a rectangular channel we have ![Area=Depth\times Width](https://tex.z-dn.net/?f=Area%3DDepth%5Ctimes%20Width)
Applying values in the continuity equation and since the width of the channel remains constant 3.0 m we have
Answer:
yes i have 2 huge bins of it
Explanation:
Answer:
c. less than 60 mi/h
Explanation:
To calculate the average speed of the bus, we need to calculate the total distance traveled by the bus, as well as the total time of travel of the bus.
Total Distance Traveled = S = 100 mi + 100 mi
S = 200 mi
Now, for total time, we calculate the times for both speeds from A to b and then B to C, separately and add them.
Total Time = t = Time from A to B + Time from B to C
t = (100 mi)/(50 mi/h) + (100 mi)(70 mi/h)
t = 2 h + 1.43 h
t = 3.43 h
Now, the average speed of bus will be given as:
Average Speed = V = S/t
V = 200 mi/3.43 h
<u>V = 58.33 mi/h</u>
It is clear from this answer that the correct option is:
<u>c. less than 60 mi/h</u>