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nydimaria [60]
2 years ago
5

You are designing a 200mm long x 100mm wide x 50mm deep rectangular housing, with a wall width of 1.5 mm, and 1 degree draft. Yo

u wish to eject by pushing on the inner bottom surface, near the walls (through the core) with pins no bigger than 3 mm diameter. The coefficient of friction is predicted to be 0.5. The material specified is Inspire 702 polypropylene, which has a modulus of 1740 MPa, a yield strength of 21 MPa, a solidification temp of 176C, an ejection temperature, DTUL, of 80C. Its coefficient of thermal expansion is 9.5e-5 m/m-C. The overall length of the pins are 300 mm and the pin material material has modulus of 200 GPa. What is the minimum amount of pins required
Engineering
1 answer:
Nimfa-mama [501]2 years ago
6 0
365gpa I don’t even know what it is but this is with 10 point and I need it
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The sliders A and B are connected by a light rigid bar of length l = 20 in. and move with negligible friction in the slots, both
DedPeter [7]

Answer:

Explanation:

Given:

- The Length of the rigid bar L = 20 in

- The position of slider a, x_a = 16 in

- The position of slider b, y_b

- The velocity of slider a, v_a = 3 ft /s

- The velocity of slider b, v_b

- The acceleration of slider a, a_a

- The acceleration of slider b, a_b

Find:

-Determine the acceleration of each slider and the force in the bar at this instant.

Solution:

- The relationship between the length L of the rod and the positions x_a and x_b of sliders A & B is as follows:

                               L^2 = x_a^2 + y_b^2   ....... 1

                               y_b = sqrt( 20^2 - 16^2 )

                               y_b = 12

- The velocity expression can derived by taking a derivation of Eq 1 with respect to time t:

                               0 = 2*x_a*v_a + 2*y_b*v_b

                               0 = x_a*v_a + y_b*v_b   ..... 2

                               0 = 16*36 + 12*v_b

                               v_b = - 48 in /s = -4 ft/s

- Similarly, the acceleration expression can be derived by taking a derivative of Eq 2 with respect to time t:

                               0 = v_a^2 + x_a*a_a + v_b^2 + y_b*a_b

                               0 = 9 + 4*a_a/3 + 16 + a_b

                               4*a_a/3 + a_b = -25

                               4*a_a + 3*a_b = -75  .... 3

- Use dynamics on each slider. For Slider A, Apply Newton's second law of motion in x direction:

                               F_x = m_a*a_a

                               P - R_r*16/20 = m_a*a_a

                               

- For Slider B, Apply Newton's second law of motion in y direction:

                               F_y = m_b*a_b

                               - R_r*12/20 = m_b*a_b

- Combine the two dynamic equations:

                               P - 4*m_b*a_b / 3 = m_a*a_a

                               3P = 3*m_a*a_a + 4*m_b*a_b  ... 4

- Where,                  P = Is the force acting on slider A

                               P , m_a and m_b are known quantities but not given in question. We are to solve Eq 3 and Eq 4 simultaneously for a_a and a_b.                    

5 0
3 years ago
an electric circuit includes a voltage source and two resistances (50 and 75) in parallel. determine the voltage source required
ASHA 777 [7]

Answer:

The voltage source required to provide 1.6 A of current through the 75 ohm resistance is 120 V.

Explanation:

Given;

Resistance, R₁ = 50Ω

Resistance, R₂ = 75Ω

Total resistance, R = (R₁R₂)/(R₁ + R₂)

Total resistance, R = (50 x 75)/(125)

Total resistance, R = 30 Ω

According to ohms law, sum of current in a parallel circuit is given as

I = I₁ + I₂

I = \frac{V}{R_1} + \frac{V}{R_2}

Voltage across each resistor is the same

1.6 = \frac{V}{R_2}  

V = 1.6 x R₂

V = 1.6 x 75

V = 120 V

Therefore, the voltage source required to provide 1.6 A of current through the 75 ohm resistance is 120 V.

This voltage is also the same for 50 ohms resistance but the current will be 2.4 A.

3 0
3 years ago
Read 2 more answers
Solid rockets can experience significant 2 phase flow. a) True b) False
dezoksy [38]

Answer:

the answer is false solid rockets can experience significant 2 phase flow

8 0
3 years ago
calculate the magnitude of the force acting on the pin at D. Pin C is fixed in DE and bears against the smooth slot in the trian
Olenka [21]

Answer:

hello your question lacks the required diagram attached below is the diagram

answer : 58.47 N

Explanation:

The magnitude of the force acting on the Pin D

Fd = \sqrt{Dx^2 + Dy^2}

    = \sqrt{16.80^2 + 56^2}

    = 58.465 N

Dx = 16.80 N

Dy = 56 N

hello attached below is the detailed solution

8 0
3 years ago
PPE is the first level of protecting an employee from hazards on the job site.
gayaneshka [121]

Answer:

The answer is B) False

8 0
3 years ago
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