Answer:
yeah,The oxidation state of an atom does not represent the "real" charge on that atom, or any other actual atomic property.Hydrogen has OS = +1, but adopts −1 when bonded as a hydride to metals or metalloids. Oxygen in compounds has OS = −2. This set of postulates covers .
Explanation:
Answer:
c : 13%
Explanation:
Data Give:
Experimental density of vanadium = 6.9 g/cm³
percent error = ?
Solution:
Formula used to calculate % error
% error = [experimental value -accepted value/accepted value] x 100
The reported accepted density value for vanadium = 6.11 g/cm³
Put value in the above equation
% error = [ 6.9 - 6.11 / 6.11 ] x 100
% error = [ 0.79 / 6.11 ] x 100
% error = [ 0.129] x 100
% error = 12.9
Round to the 2 significant figure
% error = 13 %
So, option c is correct
Answer:
52.0004 grams of mass of potassium superoxide is required
Explanation:
Let moles carbon dioxide gas be n at 22.0 °C and 767 mm Hg occupying 8.90 L of volume.
Pressure of the gas,P = 767 mm Hg = 0.9971 atm
Temperature of the gas,T = 22.0 °C = 295.15 K
Using an ideal gas equation to calculate the number of moles.


n = 0.3662 mol

According to reaction, 2 moles of carbon-dioxide reacts with 4 moles of potassium superoxide.
Then 0.3662 mol of of carbon-dioxide will react with:
of potassium superoxide.
Mass of 0.7324 mol potassium superoxide:
0.7324 mol × 71 g/mol = 52.0004 g
52.0004 grams of mass of potassium superoxide is required.