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omeli [17]
3 years ago
8

A student drew a diagram of the quantum model of an atom, as shown.

Chemistry
1 answer:
Licemer1 [7]3 years ago
6 0

Answer:

Explanation:

The diagram is correct because electrons are present in distinct energy levels around the nucleus.

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Methyl bromide (CH3Br) is produced naturally by fungi. Methyl bromide has also been used in agriculture as a fumigant, but this
Troyanec [42]

Answer:

See image attached for structure of CH3Br

Explanation:

A lewis structure structure is a representation of a covalent compound in which dots are used to show valence electrons, lone pairs and bonding electrons. The system was introduced by sir G.N Lewis in 1916 in his article titled 'Atom and Molecule'. They are also called dot electron diagrams of molecules. CH3Br molecule contains a total of fourteen electrons. Valence electrons are shown by dots around the atom of each element as clearly seen in the image attached.

8 0
3 years ago
Calculate the solubility of copper(II) hydroxide, Cu(OH)2, in g/L​
Oduvanchick [21]

Answer:

Ksp = [ Cu+² ] [ OH-] ²

molar mass Cu(oH )2 ==> M= 63.546 (1) + 16 (2) + 1 (2) = 97.546 g/mol

Ksp = [ Cu+² ] [ OH-] ²

Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰

|__________|___<u>Cu</u><u>+</u><u>²</u><u> </u>__|_<u>2</u><u>OH</u><u>-</u>____|

|<u>Initial concentration(M</u>)|___<u>0</u>__|_<u>0</u>______|

<u>|Change in concentration(M)</u>|_<u>+S</u><u> </u>|__<u>+2S</u>__|

|<u>Equilibrium concentration(M)|</u><u>_S</u><u> </u><u>_</u><u>|</u><u>2S___</u><u>|</u>

Ksp = [ Cu+² ] [ OH-] ²

2.2 ×10-²⁰ = (S)(2S)²= 4S³

s =  \sqrt[3]{ \frac{2.2 \times  {10}^{ - 20} }{4} }  = 1.8 \times  {10}^{ - 7}

S = 1.8 × 10-⁷ M

The molar solubility of Cu(OH)2 is 1.8 × 10-⁷ M

Solubility of Cu (OH)2 =

Cu (OH)2 =  \frac{1.8 \times  {10}^{ - 7} mol \:Cu (OH)2 }{1L}  \times  \frac{97.546 \: g \: Cu (OH)2}{1 \: mol \: Cu (OH)2}  \\  = 1.75428 \times 10 ^{ - 5}

<h3>Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L</h3>

I hope I helped you^_^

8 0
3 years ago
According to the equation below, how many moles of PbO are required to generate 3.88×1023 nitrogen molecules?
saul85 [17]

Answer:

1.935 mole

Explanation:

We'll begin by calculating the number of mole present in 3.88x10^23 molecules of nitrogen(N2). This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. Therefore 1 mole of N2 contains 6.02x10^23 molecules.

Now if 1 mole of N2 contains 6.02x10^23 molecules,

Then Xmol of N2 will contain 3.88x10^23 molecules i.e

Xmol of N2 = (3.88x10^23)/6.02x10^23

Xmol of N2 = 0.645 mole

Now, we can obtain the number of moles of PbO required to generate 3.88x10^23 molecules (i.e 0.645 mole) of N2. This is illustrated below:

The equation for the reaction is given below:

3PbO + 2NH3 → 3Pb + N2 + 3H2O

From the balanced equation above, 3 moles of PbO produced 1 mole of N2.

Therefore, Xmol of PbO will produce 0.645 mole of N2 i.e

Xmol of PbO = 3 x 0.645

Xmol of PbO = 1.935 mole.

From the calculations made above,

1.935 mole of PbO will produce 3.88x10^23 molecules of nitrogen (N2).

8 0
3 years ago
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I think b is the answer 
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3 years ago
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I think the answer is c since the it’s looking at NW, the wind is coming from SE
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2 years ago
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