6,3 L = 6300 mL
..................
1,79×10^-4g -------- 1 mL
Xg --------------------- 6300 mL
X = 0,000179×6300
X = 1,1277g ≈ 1,1g
:•)
Answer:
Molarity = 0.08 M
Explanation:
Given data:
Mass of sodium carbonate = 10.6 g
Volume of water = 1.25 L
Molarity of solution = ?
Solution:
First of all we will calculate the moles of solute.
Number of moles = mass/molar mass
Number of moles = 10.6 g/ 106 g/mol
Number of moles = 0.1 mol
Formula:
Molarity = moles of solute / volume of solution in L
Now we will put the values in formula.
Molarity = 0.1 mol / 1.25 L
Molarity = 0.08 M
The greatest aqueous freezing point is (D) 0.10 KCI
<span>It becomes an </span>ion<span>. An atom that gains a negative electron, it becomes a negative </span>ion<span>. If it loses an electron it becomes a positive </span>ion<span>.</span>
Hope this helps!