Answer:
Quadratic equation follows form: ax^2 + bx + c = 0
a = 8
b = - 6
c = 13
The solution of x is x = 0, x =2 and x = -5
<h3>How to solve for the unknown?</h3>
The equation is given as:
2x^3+6x^2-20x=0
Factor out x
x(2x^2+6x-20)=0
Split the equation
x = 0 or 2x^2+6x - 20=0
Solve for x in 2x^2+6x - 20=0
Expand the equation
2x^2 + 10x - 4x - 20 = 0
Factorize the equation
(2x - 4)(x +5) = 0
Split the equation
2x - 4 = 0 and x + 5 = 0
Solve for x
x =2 and x = -5
Hence, the solution of x is x = 0, x =2 and x = -5
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195 is the answer because you replace x with 10
Step-by-step explanation:
825-630=195
