All categories

2 years ago

Hurry pls need help look at picture below

Mathematics

1 answer:

jenyasd209 [6]2 years ago

3 0

V = S*h
h = V/S = 250*pi / 50*pi = 5 m

You might be interested in

Evaluate the following expression.<br> 12÷4×32+(4−2)5

sergij07 [2.7K]

Answer:

answer is 111

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A girl is snorkeling 1 meter below sea level and then dives down another 4.5 meters. How far below sea level is the girl?

san4es73 [151]

Answer:

5.5 Meters below sea level

Step-by-step explanation:

Since sea level is at 0 meters, the girl is already 1 meter below sea level. When she dives down another 4.5 meters, you just add

1 + 4.5 = 5.5

and that's your answer

4 0

3 years ago

What is the quotient for 11/8 ÷ 3/4<br> And solve

Andrew [12]

Answer:

Decimal Form:

1.833333 (add a line over 3 because the answer is 1.83 repeated)

Mixed Number Form:

1 5/6

6 0

3 years ago

Write the standard equation of the circle with the given center and passes through the given point. Center (7,-2); Point= (1,-6)

vodomira [7]

Answer:

(x - 7)² + (y + 2)² = (2√13)²

Step-by-step explanation:

We already know that the center is at (7, -2), but must find the radius. The radius is the distance between the points (7, -2) and (1, -6):

r = √ [6² + 4²] ) = √(36 + 16) = √52 = √4√13 = 2√13.

Then the desired equation is (x - 7)² + (y + 2)² = (2√13)²

6 0

3 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

3 years ago