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Allisa [31]
4 years ago
15

Can anyone pls solve this..is the answer 0

Mathematics
1 answer:
mrs_skeptik [129]4 years ago
4 0

Answer:

0

Step-by-step explanation:

Simplify the following:

81^(1/4) - 8 216^(1/3) + 15 32^(1/5) + sqrt(225)

Hint: | Simplify radicals.

216^(1/3) = (6^3)^(1/3) = 6:

81^(1/4) - 86 + 15 32^(1/5) + sqrt(225)

Hint: | Simplify radicals.

32^(1/5) = (2^5)^(1/5) = 2:

81^(1/4) - 8×6 + 15×2 + sqrt(225)

Hint: | Simplify radicals.

81^(1/4) = (3^4)^(1/4) = 3:

3 - 8×6 + 15×2 + sqrt(225)

Hint: | Multiply -8 and 6 together.

-8×6 = -48:

3 + -48 + 15×2 + sqrt(225)

Hint: | Multiply 15 and 2 together.

15×2 = 30:

3 - 48 + 30 + sqrt(225)

Hint: | Look for the difference of two identical terms.

(-48 + 30 + sqrt(225)) + 3 = 0:

Answer: 0

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Answer:

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Given four pair of events:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards

2. Drawing a 2 and drawing a 4 with replacement from a standard deck of cards

3. Drawing a heart and then drawing a spade without replacement from a standard deck of cards

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Mutually exclusive events do not have any case in common.

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Now, let us have a look at the given options one by one:

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4. Drawing a jack and then drawing a 7 without replacement from a standard deck of cards.

Separate cards are drawn one after the other, so not mutually exclusive.

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